Question

我有两个要比较的字典文件。我需要知道一个字典中的值是否出现在另一个字典中。键是不一样的，所以我不能基于键。

目标：

两个词典中都存在相同的值吗？
打印其他字典中未出现的值。
使用Keys创建一个新词典，从匹配的词典和打印词典到屏幕的值。

我可以搜索两个字典并找到69个不同的条目。

我的问题是：

我怀疑有一种更简单的方法可以做到这一点
我怀疑整体方法更好。
我不会在匹配时用两个值/键创建第三个字典。

当前代码：

#!/usr/bin/python

# Open Files and Build dictionaries.

ackg2shipping = open('AirCheckG2_ShippingLog.txt', 'r', encoding='ascii')
dAckg2 = {}
for line in ackg2shipping:
    if not line.strip():
        continue
    row = line.split(',')
    # creating unique key as one does not exist in file:
    mfgDate = row[2]
    serialNumber = row[5]
    dAckg2[mfgDate] = serialNumber

macAddressLog = open('MacAddress.dat', 'r', encoding='ascii')
dMacaddress = {}
for line in macAddressLog:
    if not line.strip():
        continue
    row = line.replace(", ", ",").split(',')
    macAddress = row[0]
    serialNum2 = row[1]
    if serialNum2.find("_2") != -1:
        continue
    if serialNum2.find("HM") != -1:
        continue
    if serialNum2.find("-") != -1:
        continue
    if serialNum2.find("Min") != -1:
        continue
    if serialNum2.find("Max") != -1:
        continue
    dMacaddress[macAddress] = serialNum2

for ackValue, macValue in zip(dAckg2.items(), dMacaddress.items()):
        if ackValue == macValue:
            print('Ok', ackValue, macValue)
        else:
            print('Not', ackValue, macValue)


match = 0
nomatch = 0

for ackKey, ackValue in dAckg2.items():
    for macKey, macValue in dMacaddress.items():
        if ackValue == macValue:
            # print("Debug: ", macValue, ackValue, "Match")
            match += 1
        else:
            # print("no match")
            # print("Debug: ", macValue, ackValue)
            nomatch += 1

print("Matched: ", match)
print("Not Matched:", nomatch)

match = 0
nomatch = 0
for macKey, macValue in dMacaddress.items():
    for ackKey, ackValue in dAckg2.items():
        if macValue == ackValue:
            # print("Debug: ", macValue, ackValue, "Match")
            match += 1
        else:
            # print("no match")
            # print("Debug: ", macValue, ackValue)
            nomatch += 1

print("Matched: ", match)
print("Not Matched:", nomatch)
missingSerials = (len(dAckg2) - match)
# noinspection PyPep8
print(missingSerials)

Answer 1

如果您只关心这些值，那么dict.values()方法可能就是您想要的。

d1_values = set(d1.values())
d2_values = set(d2.values())
in_both = d1_values & d2_values
not_in_both = d1_values ^ d2_values

我不确定你的第三个要求究竟是什么。是这样的吗？

new_dict = {}
for k, v in d1.items():
    if v in in_both:
       new_dict.update((k, v))
for k, v in d2.items():
    if v in in_both:
        new_dict.update((k, v))
print(new_dict)

Python读取两个字典比较值并创建第三个字典

1 个答案: