Question

while True:
    game_info(player_1, player_2, wins_1, wins_2)
    wins_1, wins_2 = move(board, wins_1, wins_2)  # move() sætter et 'tegn' på board og returner win1/win2


    if wins_1 or wins_2 == 1:
        new_round = input("Do you want to play again?\nType yes or no: ").lower()


        if new_round == "yes" or new_round == "y":  # hvis skal spille igen clear board.
            board = [ ['|   ', '|   ', '|   '], ['|   ', '|   ', '|   '], ['|   ', '|   ', '|   '] ]
            print("_____________________________________________________________\n" \
                  "player_2: %s is going to start, with the sign: %s|" % (player_2, sign))


        elif new_round == "no" or new_round == "n":  # hvis ikke: print hvem der vandt flest runder
            pass

        else:
            """HERE I WANT IT TO REPEAT IT ALL EXCEPT FOR THE TWO FIRST "game_info", and "move"  """

在else语句中，它应该重复整个＆＃34;而True＆＃34;除了第一个＆＃34; game_info＆＃34;和＆＃34;移动＆＃34;功能。哪个应该被跳过。这种方式在else语句之后立即结束，并要求玩家进行另一轮。

Answer 1

我想你只是在循环外添加一个名为skip（或任何）的布尔值设置为false，并在else的情况下更改它。

然后将要排除的函数移动到

中

if not skip:
    #Functions that might be skipped

应该以低成本和干净的方式完成工作。

重复功能，但重复时;最简洁的方法是跳过两个函数调用

1 个答案: