Question

我有一个具有类似表单输入名称的表单，我想将其插入到数据库表的不同行中。但是当我提交表单时，不会插入具有类似表单输入名称的输入。

这是我的观点

<div class="row">

          <div class="col-xs-12">
            <div class="item-block">
              <div class="item-form">

                <button class="btn btn-danger btn-float btn-remove"><i class="ti-close"></i></button>

                <div class="row">
                  <div class="col-xs-12 col-sm-6">
                    <div class="form-group">
                      <input type="text" name="skills_name[]" class="form-control" placeholder="Skill name, e.g. HTML">
                    </div>
                  </div>

                  <div class="col-xs-12 col-sm-6">

                    <div class="form-group">
                      <div class="input-group">
                        <input type="text" name="skills_proficiency[]" class="form-control" placeholder="Skill proficiency, e.g. 90">
                        <span class="input-group-addon">%</span>
                      </div>
                    </div>

                  </div>
                </div>

              </div>
            </div>
          </div>

          <div class="col-xs-12 duplicateable-content">
            <div class="item-block">
              <div class="item-form">

                <button class="btn btn-danger btn-float btn-remove"><i class="ti-close"></i></button>

                <div class="row">
                  <div class="col-xs-12 col-sm-6">
                    <div class="form-group">
                      <input type="text" name="skills_name[]" class="form-control" placeholder="Skill name, e.g. HTML">
                    </div>
                  </div>

                  <div class="col-xs-12 col-sm-6">

                    <div class="form-group">
                      <div class="input-group">
                        <input type="text" name="skills_proficiency[]" class="form-control" placeholder="Skill proficiency, e.g. 90">
                        <span class="input-group-addon">%</span>
                      </div>
                    </div>

                  </div>
                </div>

              </div>
            </div>
          </div>

          <div class="col-xs-12 text-center">
            <br>
            <button class="btn btn-primary btn-duplicator">Add experience</button>
          </div>


        </div>

      </div>
    </section>
    <!-- END Skills -->

控制器：

function _get_skills_data(){

    $data4['skills_name'] = $this->input->post('skills_name', TRUE);
    $data4['skills_proficiency'] = $this->input->post('skills_proficiency', TRUE);
    $session_data = $this->session->userdata('logged_in');
    $data4['user_id'] = $session_data['user_id'];

    return $data4;

}

if ($this->form_validation->run($this) == FALSE)
            {
                    $this->add_resume();
            }
            else
            {

                    $data4 = $this->_get_skills_data();


                    $this->User_model->insert_resume('skills',$data4);

                    $this->session->set_flashdata('message', '<div class="alert alert-success">Resume Added</div>');


                    redirect('user/manage_resume', 'refresh');
            }

模型：

function insert_resume($table, $data){

$query = $this->db->insert($table, $data);
return $this->db->insert_id();

}

请问我出错了什么，我已经阅读了一些对我不起作用的问题。谢谢！

Answer 1

根据Blinkydamo的评论你需要循环你的帖子数据，因为你试图将这些作为一个数组插入

尝试这样的事情：

The worker process failed to pre-load .Net Runtime version No Managed Code.

和您的第二个控制器功能代码段

function _get_skills_data()
{
    $arrData = array();
    $arrPostSkillsName = $this->input->post('skills_name', TRUE);
    $arrPostSkillsProficiency = $this->input->post('skills_proficiency', TRUE);
    $session_data = $this->session->userdata('logged_in');

    $count = count($arrPostSkillsName);

    for($i=0;$i<$count;$i++)
    {
        $arrItemData = array();
        $arrItemData['skills_name'] = $arrPostSkillsName[$i];
        $arrItemData['skills_proficiency'] = $arrPostSkillsProficiency[$i];
        $arrItemData['user_id'] = $session_data['user_id'];

        $arrData[] = $arrItemData;
    }

    return $arrData;
}

使用codeigniter

1 个答案: