Index和orientdb

Question

我在orientdb中创建了一个带有图形所有边的索引。进行查询：

select from index: Where unique_edge key = # 9: 1

因为我得到了Web控制台

OCompositeKey {keys = [# 9: 1, # 9: 0]}
OCompositeKey {keys = [# 9: 1, # 12: 0]}

和java控制台中的相同查询

# 3: -1
# 3: -1

我需要获取边缘的顶点

# 9: 1, # 9: 0, # 12: 0.

有人可以帮助我吗？

Answer 1

您可以使用

select both() from #9:1

因为你的索引不会提高速度。

希望它有所帮助。

Answer 2

创建de index

OCommandSQL declareIn= new OCommandSQL();
declareIn.setText("CREATE PROPERTY E.in LINK");
OCommandSQL declareOut= new OCommandSQL();
declareOut.setText("CREATE PROPERTY E.out LINK");
OCommandSQL createIndexUniqueEdge= new OCommandSQL();
createIndexUniqueEdge.setText("CREATE INDEX unique_edge ON E (in, out) UNIQUE");
orientDBGraph.command(declareIn).execute();
orientDBGraph.command(declareOut).execute();               
orientDBGraph.command(createIndexUniqueEdge).execute();

System.out.println(createIndexUniqueEdge.getText());

String query10 = "select from index:unique_edge where key=#9:1";
Iterable<OrientVertex> res10 = orientDBGraph.command(new OCommandSQL(query10)).execute();

while(res10.iterator().hasNext()){
    OrientVertex source = res10.iterator().next();

    System.out.println(source.getId());


}