Question

我有一个问题，我的JSON在XCode中作为NIL输出，即使我在浏览器中测试它报告正确的值。

$player1Id = array();
$player1Id = getPlayer1Id($player1name,$communityId);

public function getPlayer1Id($playerName, $communityId)
{

$returnValue = array();

$sql = "SELECT users.id\n"
. "FROM users\n"
. "join community_players\n"
. "on community_players.player_id=users.id \n"
. "WHERE users.user_name = '".$playerName."' AND community_players.community_id = '".$communityId."'";

$result = $this->conn->query($sql);
    if($result != null && (mysqli_num_rows($result) >= 1 )){
        $row = $result -> fetch_array(MYSQLI_ASSOC);
        if(!empty($row)){
            $returnValue = $row['id'];
        }
    }
    return $returnValue;
}

echo json_encode(array($player1Id));

如果我在浏览器中使用URL中的一组值进行测试，则输出正确：

[ “31”]

这是我的Swift功能：

func submit(action: UIAlertAction){
//    print (homePlayerLabel.text!,":",homeTeamLabel.text!,homeGoals,"(",player1result!,") - ", awayPlayerLabel.text!,":",awayTeamLabel.text!,awayGoals,"(",player2result!,")")


    // Send user data to server side

    let myUrl = URL(string: "http://www.quasisquest.uk/KeepScore/submitScore.php");

    var request = URLRequest(url:myUrl!);
    request.httpMethod = "POST";

    let postString = "communityId=\(communityId!)&player1name=\(homePlayerLabel.text!)&player1team=\(homeTeamLabel.text!)&player1goals=\(homeGoals)&player1result=\(player1result!)&player2name=\(awayPlayerLabel.text!)&player2team=\(awayTeamLabel.text!)&player2goals=\(awayGoals)&player2result=\(player2result!)";

    print (postString)
    request.httpBody = postString.data(using: String.Encoding.utf8);


    let task = URLSession.shared.dataTask(with: request) { (data: Data?, response: URLResponse?, error: Error?) in


        DispatchQueue.main.async
            {


                if error != nil {
                    print("error=\(error)")
                    return
                }

                do {

                    let json = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]
                    print (json)

                    if let parseJSON = json {

                        let returnValue = parseJSON["status"] as? String

                        if( returnValue == "Success")
                        {
                            let myAlert = UIAlertController(title: "Alert", message: "Registration successful", preferredStyle: UIAlertControllerStyle.alert);


                            let okAction = UIAlertAction(title: "OK", style: UIAlertActionStyle.default){(action) in

                                self.dismiss(animated: true, completion: nil)

                            }

                            myAlert.addAction(okAction);
                            self.present(myAlert, animated: true, completion: nil)

                        } else {


                            let errorMessage = parseJSON["message"] as? String
                            if(errorMessage != nil)
                            {

                                self.displayMyAlertMessage(userMessage: errorMessage!);

                            }

                        }

                    }
                } catch{
                    print(error)
                }



        }

    }

    task.resume()



}

然而，当我在Xcode中将print (json)报告为：

NIL

我有什么明显的东西在看吗？

Answer 1

我认为您将 php更新为7.1 我将更新php更新为7.1 try to put mysql_query('SET CHARACTER SET utf8')我遇到同样的问题我觉得它可以解决您的问题

JSON_encode在浏览器中正确输出，但在Swift输出'nil'中打印（json），为什么？

1 个答案: