我是laravel的新手。我需要使用where condition(其中exam_id = 1)向表中的所有记录发送电子邮件。每条记录都会收到电子邮件的消息是它自己的名称和电子邮件。已经存储在表中。可以为此提出任何建议吗?
提前谢谢
public function sendmail(Request $request) {
$email = DB::table('student')->select('email','exam_id')->where('exam_id','=','1')->get();
$email= mysql_query("SELECT email FROM student WHERE exam_id='1' ;");
$title = $request->input('title');
$content = $request->input('content');
if(mysql_num_rows($email))
{
while($elist_result = mysql_fetch_array($email))
{
Mail::send('email', ['title' => $title, 'content' => $content],function ($message)
{
$message->from('dhivya@authorselvi.com', 'dhivya');
$message->to('dhivya@authorselvi.com');
$message->cc($elist_result);
$message->subject("Hello");
} );
}
}
return response()->json(['message' => 'message send successfully']);
}
答案 0 :(得分:1)
public function sendmail(Request $request) {
$email = DB::table('student')->select('email','exam_id')->where('exam_id','=','1')->get();
$title = $request['title'];
$content = $request['content'];
foreach($email as $email) {
Mail::send('email', ['title' => $title, 'content' => $content],function ($message)
{
$message->from('dhivya@authorselvi.com', 'dhivya');
$message->to($email->email);
$message->subject("Hello");
});
}
return response()->json(['message' => 'message send successfully']);
}
答案 1 :(得分:0)
我看到你坚持使用清除PHP ,而且在使用Laravel框架时这是错误的。
public function sendmail(Request $request) {
$emails = DB::table('student')->select('email','exam_id')->where('exam_id','=','1')->get();
$title = $request['title'];
$content = $request['content'];
foreach($emails as $email) {
Mail::send('email', ['title' => $title, 'content' => $content],function ($message)
{
$message->from('dhivya@authorselvi.com', 'dhivya');
$message->to($email->email);
$message->subject("Hello");
});
}
return response()->json(['message' => 'message send successfully']);
}
看看我编辑的代码并试一试。