我尝试将当前的user_id保存到数据库中的教育表。但是,user_id的数据未填充。这是我的代码。
模特
public function rules()
{
return [
[['year', 'fieldstudy', 'institute', 'grade'], 'required'],
[['user_id'], 'integer'],
[['year', 'fieldstudy', 'institute', 'grade'], 'string', 'max' => 255],
];
}
public function attributeLabels()
{
return [
'education_id' => 'Education ID',
'user_id' => 'User ID',
'year' => 'Year',
'fieldstudy' => 'Fieldstudy',
'institute' => 'Institute',
'grade' => 'Grade',
];
}
public function getUser()
{
return $this->hasOne(User::className(), ['user_id' => 'user_id']);
}
在控制器
public function actionCreate()
{
$model = new Education();
$model->user_id =Yii::$app->user->id;
if ($model->load(Yii::$app->request->post()) && $model->save()) {
return $this->redirect(['view', 'id' => $model->education_id]);
} else {
return $this->render('create', [
'model' => $model,
]);
}
}
如何解决问题并修复代码?感谢
答案 0 :(得分:0)
将Yii::$app->user->id
更新为Yii::$app->user->identity->id
。
public function actionCreate()
{
$model = new Education();
if ($model->load(Yii::$app->request->post())) {
$model->user_id =Yii::$app->user->identity->id;
if($model->save()){
return $this->redirect(['view', 'id' => $model->education_id]);
}
}
return $this->render('create', [
'model' => $model,
]);
}
答案 1 :(得分:0)
你必须检查两件事
Yii::$app->user->id
或Yii::$app->user->id
使用Yii2调试器通过使用代码
检查我们获得的用户id值是否正确Yii::info("User id=".Yii::$app->user->id);
您必须在控制器中尝试的完整代码如下所示
public function actionCreate() {
$model = new Education();
//checking whether we are getting the logged in user id value
Yii::info("User id=".Yii::$app->user->id);
$model->user_id = Yii::$app->user->id;
if ($model->load(Yii::$app->request->post()) && $model->save()) {
//checking here the saved user id value in table
Yii::info("checking User id after saving model=".$model->user_id);
return $this->redirect(['view', 'id' => $model->education_id]);
} else {
return $this->render('create', [
'model' => $model,
]);
}
}
现在运行应用程序后,您可以使用Yii2调试器检查在各个位置的用户ID中设置的值。