Question

使用warp.js的这个脚本从当前日期开始运行良好。我似乎无法弄清楚如何从1986年1月2日之前的日期开始工作？

warp.js https://github.com/mattbradley/warpjs/blob/master/README.md

谢谢！

    <body>
        <script src="warp.js"></script>


        <div id="container"></div>
        <span id="info"></span><br>
        <span id="time"></span>
        <span id="time2"></span>

        <script>


        setInterval(function() {

          //specify a start date here like Jan 2 1986

          Date.warp.speed(3);
          var now = new Date;
          //new date put out the warped start date above?

          var dateD = [now.getMonth() + 1, now.getDate(), now.getFullYear()];
          var dateE = [now.getHours(), now.getMinutes(), now.getSeconds()];
          var MDY = dateD.join("/");
          var HMS = dateE.join(":");
          time.innerHTML = (MDY);
          time2.innerHTML = (HMS);

        }, 1000);
        </script>

    </body>

    </html>

Answer 1

我想出来了。你必须使用clock（）函数，所以设置你的自定义日期，然后它将从该自定义日期变形。

Table table = new Table();
Row row = new Row();
Cell cell = new Cell();
using(Streamreader sr = new Streamreader(file))
{
    string str;
    while((str = sr.ReadLine()) != null)
    {
       if(str.Includes("Marker"))
       {
          row = table.AddRow();
          cell = row.Cells[0]
          cell = row.Cells[1] // actually I use a counter variable, cause my table has 6 cells consistent.
       }
    }
}

Warp.js日期从上一个日期开始

1 个答案: