Question

三天之后无法弄清楚如何按下“下一步”按钮，并且会在标签小部件中为sight_word显示列表中的随机单词。任何帮助是极大的赞赏。

class SightWord(BoxLayout):
    pass

class SightWordApp(App):
    def build(self):
        return SightWord()

# Function that selects random sight word from list
    def sight_word(self):
        word_list = ['What', 'How', 'My', 'Know', 'You']
        random_index = randrange(0,len(word_list))
        word = word_list[random_index]
        print(word)

if __name__ == '__main__':
    SightWordApp().run()

Kivy档案：

#:kivy 1.9.1

<SightWord>:

    orientation: 'vertical'
    padding: root.width * 0.01, root.height * 0.01

    BoxLayout:
        orientation: 'horizontal'

        Label:
            id: sight_word
            # This is where I want the word to change values
            text: 'XXXX'
            size_hint: 1, None
            font_size: '100sp'
            height: self.texture_size[1] + (2 * root.padding[1])

    BoxLayout:
        orientation: 'horizontal'

        Button:
            id: next_btn
            text: 'Next'
            on_press: app.sight_word()
            size_hint: 1, None
            height: self.texture_size[1] + (4 * root.padding[1])
            width: self.texture_size[1] + (4 * root.padding[1])

Answer 1

这非常简单，您只需找到正确的对象（Label）并将值传递给其text属性。我发现您已为该标签制作了id，并通过app进行了调用，所以让我们使用它：

<强> .kv

Button:
    id: next_btn
    text: 'Next'
    on_press: app.sight_word(sight_word)  # pass id to a function
    size_hint: 1, None
    height: self.texture_size[1] + (4 * root.padding[1])
    width: self.texture_size[1] + (4 * root.padding[1])

<强>的.py

    def sight_word(self, label):  # use the id/object
        word_list = ['What', 'How', 'My', 'Know', 'You']
        random_index = randrange(0,len(word_list))
        word = word_list[random_index]
        label.text = word  # change text property to your string

在为函数

1 个答案: