Question

#!/usr/bin/env python
import socket
clientsocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
clientsocket.connect(('192.168.1.123', 5162))
clientsocket.send('getval.1')
clientsocket.close
clientsocket.bind(('192.168.1.124', 5163))
clientsocket.listen(1)
while True:
    connection, address=clientsocket.accept()
    value=connection.recv(1024)
    print value

我正在尝试让python向服务器发送消息，作为回报，服务器会响应。然而，当我执行这段代码时，它给了我

Socket.error: [Errno 10022] An invalid argument was supplied

Answer 1

好像你写了服务器和客户端的混合代码这里是一个简单的代码示例，用于套接字编程，第一个在服务器端，第二个在客户端

服务器端代码：

# server.py 
import socket                                         
import time

# create a socket object
serversocket = socket.socket(
            socket.AF_INET, socket.SOCK_STREAM) 

# get local machine name
host = socket.gethostname()                           

port = 9999                                           

# bind to the port
serversocket.bind((host, port))                                  

# queue up to 5 requests
serversocket.listen(5)                                           

while True:
    # establish a connection
    clientsocket,addr = serversocket.accept()      

    print("Got a connection from %s" % str(addr))
    currentTime = time.ctime(time.time()) + "\r\n"
    clientsocket.send(currentTime.encode('ascii'))
    clientsocket.close()

现在是客户

# client.py  
import socket

# create a socket object
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 

# get local machine name
host = socket.gethostname()                           

port = 9999

# connection to hostname on the port.
s.connect((host, port))                               

# Receive no more than 1024 bytes
tm = s.recv(1024)                                     

s.close()

print("The time got from the server is %s" % tm.decode('ascii'))

服务器只是继续监听任何客户端，当它找到新连接时，它返回当前日期时间并关闭客户端连接

Socket.error：[Errno 10022]提供了无效参数

1 个答案: