Question

拥有这个数组：

const xx = [
  {
    name: "Alex",
    income: 324300,
    total: 3030000
  },
  {
    name: "Snake",
    income: 3433000,
    total: 34323000
  },
  {
    name: "Wake",
    income: 4,
    total: 3
  }
];

如果值为int（收入和总计），我想循环遍历并执行某些操作。我该怎么做呢？

这是我到目前为止所尝试的，我真的不知道如何取出对象值并测试它是否为int

for (var key in xx) {
       var arr = xx[key];
       for( var i = 0; i < arr.length; i++ ) {
           var obj = arr[ i ];
       }
    }
        }

Answer 1

尝试：

const xx = [
  {
    name: "Alex",
    income: 324300,
    total: 3030000
  },
  {
    name: "Snake",
    income: 3433000,
    total: 34323000
  },
  {
    name: "Wake",
    income: 4,
    total: 3
  }
];

xx.forEach(item => {
  Object.keys(item).forEach(key => {
    if (!isNaN(parseInt(item[key])) && isFinite(item[key])) {
      // do something here
      console.log('INT: ' + item[key]);
    }
  });
});

Answer 2

您需要与外部交换内部。并使用：

typeof xx[i][k] === "number"或xx[i][k] === +xx[i][k]检查值是否为一个号码。
parseInt(xx[i][k]) === xx[i][k]检查值是否为整数号。

参见示例：

const xx = [{
  name: "Alex",
  income: 324300,
  total: 3030000
}, {
  name: "Snake",
  income: 34.33000,
  total: 34323000
}, {
  name: "Wake",
  income: 4,
  total: 3
}];
for (var i = 0; i < xx.length; i++) {
  for (var k in xx[i]) {
    //if(parseInt(xx[i][k]) === xx[i][k]) //integer
    //if(typeof xx[i][k] == "number") //number
    if (xx[i][k] === +xx[i][k]) { //number
      console.log(k + ": " + xx[i][k]);
    }
  }
}

Javascript循环遍历字符串和整数数组

2 个答案: