我一直试图在winforms vb.net应用程序中获得以下结果
此图片中的每个圆弧或圆圈都是可点击的, 可点击的弧线以粉红色着色。
我设法编写以下代码
Private Sub Form1_Paint(ByVal sender As System.Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles MyBase.Paint
'Create pen objects
Dim p As New Pen(Color.Green, 30)
Dim p1 As New Pen(Color.Yellow, 30)
Dim p2 As New Pen(Color.Red, 30)
Dim p3 As New Pen(Color.Blue, 30)
'Create rectangle objects
Dim rt As New Rectangle(160, 150, 80, 100)
Dim rt1 As New Rectangle(100, 150, 80, 100)
Dim rt2 As New Rectangle(130, 120, 80, 100)
Dim rt3 As New Rectangle(130, 180, 80, 100)
'Draw arcs
e.Graphics.DrawArc(p, rt, 45, -90)
e.Graphics.DrawArc(p1, rt1, -135, -90)
e.Graphics.DrawArc(p2, rt2, -45, -90)
e.Graphics.DrawArc(p3, rt3, 135, -90)
End Sub
导致以下输出。
我没想到的是:
1-如何为每个弧创建边框。
2-如何处理每个弧的点击次数。
有没有比我试图解决这个问题更好的方式。
任何帮助将不胜感激。
答案 0 :(得分:2)
特别感谢Reza Aghaei的帮助, 我在我的解决方案中使用了以下代码
编辑:改进的答案
处理图形路径,使代码更整洁
Imports System.Drawing.Drawing2D
Public Class SurfaceSelection
Private Sub SurfaceSelection_Click(sender As Object, e As MouseEventArgs) Handles Me.Click
Dim hitSurface As String = String.Empty
If GetPath(EnumsClass.SurfacesEnum.L).IsVisible(e.Location) Then
hitSurface = "L"
ElseIf GetPath(EnumsClass.SurfacesEnum.M).IsVisible(e.Location) Then
hitSurface = "M"
ElseIf GetPath(EnumsClass.SurfacesEnum.F).IsVisible(e.Location) Then
hitSurface = "F"
ElseIf GetPath(EnumsClass.SurfacesEnum.D).IsVisible(e.Location) Then
hitSurface = "D"
Else
hitSurface = "Missed"
End If
MsgBox(hitSurface)
End Sub
Private Sub SurfaceSelection_Paint(ByVal sender As System.Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles MyBase.Paint
Me.DrawPath(EnumsClass.SurfacesEnum.L, e)
Me.DrawPath(EnumsClass.SurfacesEnum.M, e)
Me.DrawPath(EnumsClass.SurfacesEnum.F, e)
Me.DrawPath(EnumsClass.SurfacesEnum.D, e)
End Sub
Private Sub DrawPath(ByVal v_bytSurface As EnumsClass.SurfacesEnum, ByVal e As System.Windows.Forms.PaintEventArgs)
Using p As GraphicsPath = GetPath(v_bytSurface)
e.Graphics.FillPath(Brushes.Green, p)
e.Graphics.DrawPath(Pens.Black, p)
End Using
End Sub
Private Function GetPath(ByVal v_bytSurface As EnumsClass.SurfacesEnum) As GraphicsPath
Dim path As New GraphicsPath
Dim center = New Point(100, 100)
Dim innerR = 70
Dim thickness = 20
Dim startAngle = getGraphicsPathAngle(v_bytSurface)
Dim arcLength = 70
Dim outerR = innerR + thickness
Dim outerRect = New Rectangle(center.X - outerR, center.Y - outerR, 2 * outerR, 2 * outerR)
Dim innerRect = New Rectangle(center.X - innerR, center.Y - innerR, 2 * innerR, 2 * innerR)
path.AddArc(outerRect, startAngle, arcLength)
path.AddArc(innerRect, startAngle + arcLength, -arcLength)
path.CloseFigure()
Return path
End Function
Private Function getGraphicsPathAngle(ByVal v_bytSurface As EnumsClass.SurfacesEnum) As Integer
Select Case v_bytSurface
Case EnumsClass.SurfacesEnum.F
Return 235
Case EnumsClass.SurfacesEnum.O
Return 0
Case EnumsClass.SurfacesEnum.L
Return 55
Case EnumsClass.SurfacesEnum.M
Return 145
Case EnumsClass.SurfacesEnum.D
Return 325
Case EnumsClass.SurfacesEnum.Unspecified
Return -1
End Select
End Function
End Class
Public Class EnumsClass
Public Enum SurfacesEnum As Byte
Unspecified = 0
F = 1
O = 2
L = 3
M = 4
D = 5
End Enum
End Class
我在下面的stackoverflow问题中使用了Reza的答案:
How to draw a circular progressbar pie using GraphicsPath in WinForm?
How can I treat the circle as a control after drawing it? - Moving and selecting shapes