对不起,这看似简单,但有人问我这个问题,我不确定。
一个空的C ++类带有什么功能?
构造, 复制构造函数, 分配, 析构函数?
是吗?还是有更多?答案 0 :(得分:45)
在C ++ 03中有4:
默认构造函数:仅在声明时声明 没有用户定义的构造函数 声明。使用时定义
复制构造函数 - 仅在用户尚未声明时才声明。如果使用则定义
复制分配运算符与上述相同
析构函数与上述相同
在C ++ 11中还有两个:
编译器也可能无法生成其中的一些。例如,如果类包含例如引用(或任何其他无法复制分配的引用),则编译器将无法为您生成复制赋值运算符。 For more information read this
答案 1 :(得分:12)
如果我定义以下类
class X
{};
编译器将定义以下方法:
X::X() {} // Default constructor. It takes zero arguments (hence default).
X::~X() {} // Destructor
X::X(X const& rhs) {}; // Copy constructor
X& operator=(X const& rhs)
{return *this;} // Assignment operator.
注意:
如果定义了 ANY 构造函数,则不会构建默认构造函数
如果用户定义了替代方法,则不会构建其他方法。
当我们有成员和基础时,默认实现更有趣:
class Y: public X
{
int a; // POD data
int* b; // POD (that also happens to be a pointer)
Z z; // A class
};
// Note: There are two variants of the default constructor.
// Both are used depending on context when the compiler defined version
// of the default constructor is used.
//
// One does `default initialization`
// One does `zero initialization`
// Objects are zero initialized when
// They are 'static storage duration'
// **OR** You use the braces when using the default constructor
Y::Y() // Zero initializer
: X() // Zero initializer
, a(0)
, b(0)
, z() // Zero initializer of Z called.
{}
// Objects are default initialized when
// They are 'automatic storage duration'
// **AND** don't use the braces when using the default constructor
Y::Y()
:X // Not legal syntax trying to portray default initialization of X (base class)
//,a // POD: uninitialized.
//,b // POD: uninitialized.
,z // Not legal syntax trying to portray default initialization of z (member)
{}
//
// Note: It is actually hard to correctly zero initialize a 'automatic storage duration'
// variable (because of the parsing problems it tends to end up a a function
// declaration). Thus in a function context member variables can have indeterminate
// values because of default initialization. Thus it is always good practice to
// to initialize all members of your class during construction (preferably in the
// initialization list).
//
// Note: This was defined this way so that the C++ is backward compatible with C.
// And obeys the rule of don't do more than you need too (because we want the C++
// code to be as fast and efficient as possible.
Y::Y(Y const& rhs)
:X(rhs) // Copy construct the base
,a(rhs.a) // Copy construct each member using the copy constructor.
,b(rhs.b) // NOTE: The order is explicitly defined
,z(rhs.z) // as the order of declaration in the class.
{}
Y& operator=(Y const& rhs)
{
X::operator=(rhs); // Use base assignment operator
a = rhs.a; // Use the assignment operator on each member.
b = rhs.b; // NOTE: The order is explicitly defined
z = rhs.z; // as the order of declaration in the class.
return(*this);
}
Y::~Y()
{
Your Code first
}
// Not legal code. Trying to show what happens.
: ~z()
, ~b() // Does nothing for pointers.
, ~a() // Does nothing for POD types
, ~X() ; // Base class destructed last.
答案 2 :(得分:7)
只需展开Armen Tsirunyan answer,这里有方法的签名:
.child {
background: none repeat scroll 0 0 #F6F6F6;
border: 1px solid #CCCCCC;
border-bottom: 1px solid #CCCCCC;
border-bottom-right-radius: 6px;
border-bottom-left-radius: 6px;
border-right: 1px solid #CCCCCC;
border-top: 1px solid #CCCCCC;
border-top-left-radius: 6px;
border-top-right-radius: 6px;
min-height: 749px;
background-color: white;
display:table;
float:right;
min-width: 900px;
position:absolute;
overflow: visible;
height:100%;
}
.parent {
overflow: visible;
min-height: 100%;
height: 100%;
padding: 13px 25px 75px 25px;
min-width: 900px;
}
答案 3 :(得分:0)
是吗?
是的,就是这样。
编译器默认生成
一个班级
使用Clang的-ast-dump
选项时,您可以看到默认生成的默认构造函数,复制构造函数和赋值运算符
prasoon@prasoon-desktop ~ $ cat empty.cpp && clang++ -cc1 -ast-dump empty.cpp
class empty
{};
int main()
{
empty e;
empty e2 = e;
{
empty e3;
e3 = e;
}
}
typedef char *__builtin_va_list;
class empty {
class empty;
inline empty() throw(); //default c-tor
//copy c-tor
inline empty(empty const &) throw() (CompoundStmt 0xa0b1050 <empty.cpp:1:7>)
//assignment operator
inline empty &operator=(empty const &) throw() (CompoundStmt 0xa0b1590 <empty.cpp:1:7>
(ReturnStmt 0xa0b1578 <col:7>
(UnaryOperator 0xa0b1558 <col:7> 'class empty' prefix '*'
(CXXThisExpr 0xa0b1538 <col:7> 'class empty *' this))))
};
答案 4 :(得分:0)