Question

我希望将用户输入作为数字，检查其有效性并将其返回。如果号码无效，我希望重复输入过程。但是如果我输入：

"5b"
"50.4"

该功能不会返回50.4。而是返回5.0，因为第一个函数调用的余数被执行。如何修复上述问题，仅获取50.4？

def inputGoal ():
    goalFiltered = ""
    print ('1: ' + str(goalFiltered))
    goal = input("Input number: ")

    for char in goal:
        matched = False
        for sign in comparator:
            if (sign == char):
                matched = True
                if (char != ','):
                    goalFiltered += sign
                elif (char == ','):
                    goalFiltered += '.'
        if (matched == False):
            print ("Please repeat input, valid characters are: 0 1 2 3 4 5 6 7 8 9 , .")
            inputGoal()
            #return
    goalFiltered = float(goalFiltered)
    return (goalFiltered)

比较器变量是：

comparator = ['0','1','2','3','4','5','6','7','8','9',',','.']

Answer 1

如果我理解你的问题，我认为你可以这样做：

while True:
    ask = input("Input the number:\t") #The \t just puts a tab so it looks nice
    if ask == float(ask):
        break
    else:
        print("The number is incorrect. Try again.")
        continue

函数返回先前的值

1 个答案: