因此,当我按下设备上的递增或递减按钮时,应用程序强制关闭。我尝试使用调试器,但似乎无法找出问题所在。它基本上是一个显示订单摘要的单个屏幕应用程序。
以下是XML代码:
<ScrollView xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity">
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin">
<TextView
android:id="@+id/name_field"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="QUANTITY!" />
<CheckBox
android:id="@+id/whipped_cream_checkbox"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:paddingLeft="24dp"
android:text="Whipped Cream"
android:textSize="16sp" />
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal">
<Button
android:layout_width="48dp"
android:layout_height="48dp"
android:onClick="decrement"
android:text="-" />
<TextView
android:id="@+id/quantity_text_view"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:paddingLeft="8dp"
android:paddingRight="8dp"
android:text="0"
android:textColor="@android:color/black"
android:textSize="16sp" />
<Button
android:layout_width="48dp"
android:layout_height="48dp"
android:onClick="increment"
android:text="+" />
</LinearLayout>
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginTop="16dp"
android:onClick="submitOrder"
android:text="Order" />
<TextView
android:id="@+id/order_summary"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:padding="16dp"/>
</LinearLayout>
</ScrollView>
JAVA代码:
package com.example.android.timeforacoffee;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.widget.TextView;
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
int quantity=0;
String priceMessage="Name: Moksh \n" + "Your total is ₹" +quantity;
public void displayQuanity(int quantity) {
TextView quantity_value=(TextView) findViewById(R.id.quantity_text_view);
quantity_value.setText(quantity);
}
/**
*This method is called when the - button is pressed.
*/
public void decrement(View view) {
displayQuanity(quantity - 1);
}
/**
*
* This method is called when the + button is clicked.
*/
public void increment(View view) {
displayQuanity(quantity + 1);
}
public void displayMessage(String priceMessage) {
TextView order_summary=(TextView) findViewById(R.id.order_summary);
order_summary.setText(priceMessage);
}
/**
* This method is called when the Order button is clicked.
*/
public void submitOrder(View view) {
displayMessage(priceMessage);
}
}
答案 0 :(得分:0)
我认为问题出在下面的代码行
quantity_value.setText(quantity);
请注意,当您将任何整数传递给setText
函数时,android会将整数视为对字符串reource的引用,并在资源文件中搜索该字符串,如果找不到该字符串,则您的应用程序将崩溃{ {1}}。
您可以通过将整数显式解析为字符串来解决此问题,如下所示
android.content.res.Resources$NotFoundException