Question

我希望有这样的东西：

SELECT
  p.name_en AS 'province_$lang',
  p.province_code AS 'province_code_$lang',
  COUNT(u.id) AS 'total_$lang',
  COUNT(u.id) AS total
FROM applications AS a 
LEFT JOIN users AS u on u.id = a.user_id 
LEFT JOIN provinces AS p on p.province_code = u.province_code
WHERE a.progress_status IN (0,1,2,3) AND IF( a.progress_status = 2,a.denial_type ,1) IN IF(a.`progress_status` = 2,(1,2,3),1)
GROUP BY u.province_code

假设我在表格中有两个字段，其中一个字段progress_status可以包含其中一个0,1,2, or 3值，另一个字段denial_type可以使用1,2, or 3，但是当denial_type为2时，progress_status只能获取其中一个值。所以我想检查progress_status是IN 0,1,2,3，对于那些progress_status为2的记录，其denial_type应为{{1} } 1,2,3

Answer 1

试试这个：

SELECT
p.name_en AS 'province_$lang',
p.province_code AS 'province_code_$lang',
COUNT(u.id) AS 'total_$lang',
COUNT(u.id) AS total
FROM applications AS a 
LEFT JOIN users AS u on u.id = a.user_id 
LEFT JOIN provinces AS p on p.province_code = u.province_code
WHERE a.progress_status IN (0,1,2,3) AND   
IF( a.progress_status = 2,  
(select denial_type from applications where denial_type IN (1,2,3)) ,1) 
GROUP BY u.province_code

在subquery条件中使用IF仅选择值为denial_type的{{1}}可能会解决您的问题。

希望它有所帮助！

Answer 2

发布聚合过滤应该可以解决问题

SELECT
  p.name_en AS 'province_$lang',
  p.province_code AS 'province_code_$lang',
  COUNT(u.id) AS 'total_$lang',
  COUNT(u.id) AS total
FROM applications AS a 
LEFT JOIN users AS u on u.id = a.user_id 
LEFT JOIN provinces AS p on p.province_code = u.province_code
GROUP BY u.province_code
HAVING SUM(a.progress_status IN (0,1,2,3))>0
AND SUM(a.progress_status = 2 AND a.denial_type IN(1,2,3))>0

Mysql如何在where子句中使用IN和IF？

2 个答案: