Question

我正在编写一个tic tac toe游戏，我陷入了代码应该检查玩家是否已赢得垂直的步骤，我知道c ++的朋友告诉我先通过COLUMNS迭代然后ROWS来制作流程更轻松。不确定它在python中是如何工作的。

所以例如玩家进入4x4表，过了一会儿这是他的结果。

[0,1,0,0]
[0,1,0,0]
[0,1,0,0]
[0,1,0,0]

他说如果我首先通过列迭代然后再行，那么它就像是：

CHECK,1,0,0
CHECK,1,0,0
CHECK,1,0,0
CHECK,1,0,0

然后列索引更改为1

0,CHECK,0,0
0,CHECK,0,0
0,CHECK,0,0
0,CHECK,0,0

抱歉说不好......

Answer 1

这样的事情？

In [22]: import numpy as np

In [23]: a=np.array(range(15)).reshape(3,5)

In [24]: a
Out[24]: 
array([[ 0,  1,  2,  3,  4],
       [ 5,  6,  7,  8,  9],
       [10, 11, 12, 13, 14]])

In [25]: [ [x[i] for x in a] for i in range(a.shape[1])]
Out[25]: [[0, 5, 10], [1, 6, 11], [2, 7, 12], [3, 8, 13], [4, 9, 14]]

Answer 2

您可以使用内置all()功能检查所有元素是否为True，
和Row-to-Column Transposition

的zip(*table)符号

mytable1 = [[0,0,0,0],[1,1,1,1],[0,0,0,0],[0,0,0,0]]
mytable2 = [[0,0,1,0],[0,0,1,0],[0,0,1,0],[0,0,1,0]]
mytable3 = [[1,0,0,0],[0,1,0,0],[0,0,1,0],[0,0,0,1]]
mytable4 = [[0,0,0,1],[0,0,1,0],[0,1,0,0],[1,0,0,0]]
mytable5 = [[0,1,0,0],[0,0,1,0],[0,1,0,0],[1,0,0,0]]
mytable6 = [[2,1,0,0],[2,0,1,0],[2,1,0,0],[2,0,1,0]]
mytable7 = [[2,1,0,0],[0,2,1,0],[0,1,2,0],[0,0,1,2]]

def hasWon(table,player_no):
    #check rows
    for row in table: 
        if all([e==player_no for e in row]):
            return True
    #check columns
    for column in zip(*table): 
        if all([e==player_no for e in column]):
            return True
    #check diagonals
    if all([table[i][i]==player_no for i in range(len(table)) ]): 
        return True
    if all([table[-i-1][i]==player_no for i in range(len(table))]):
        return True
    return False



print(hasWon(mytable1,1))
print(hasWon(mytable2,1))
print(hasWon(mytable3,1))
print(hasWon(mytable4,1))
print(hasWon(mytable5,1))
print(hasWon(mytable6,2))
print(hasWon(mytable7,2))

输出：

True
True
True
True
False
True
True

如何首先迭代列然后再行

2 个答案: