Question

在javascript中，我有一个时间字符串var time = "12:30:49PM"

我想将小时，分钟，秒和AM / PM与该字符串分开。

浏览stackoverflow我能够找到以下正则表达式分割小时，分钟和上午/下午，但我在正则表达式上非常糟糕，所以我无法弄清楚如何做秒。

 var hours = Number(time.match(/^(\d+)/)[1]);
 var minutes = Number(time.match(/:(\d+)/)[1]);
 var AMPM = time.match(/([AaPp][Mm])$/)[1];

如何通过正则表达式获得第二个

Answer 1

您可以将正则表达式与ES6数组解构结合使用：

＆＃13;

const time = "12:30:49PM"
const [hour, min, sec, period] = time.match(/\d+|\w+/g);

console.log(hour, min, sec, period);

＆＃13;

Answer 2

在您的示例中，您只需执行以下操作：

＆＃13;

var time = "12:30:49PM";   
var hours = Number(time.match(/^(\d+)/)[1]);
var minutes = Number(time.match(/:(\d+)/)[1]);
var AMPM = time.match(/([AaPp][Mm])$/)[1];
var seconds = Number(time.match(/:(\d+):(\d+)/)[2]);
console.log(hours, ":", minutes, ":", seconds, AMPM);

＆＃13;

但是，在一次通话中获取所有内容会更有效：

＆＃13;

var time = "12:30:49AM";
var matches = time.match(/^(\d+):(\d+):(\d+)([AP]M)$/i);
var hours = matches[1];
var minutes = matches[2];
var seconds = matches[3];
var AMPM = matches[4];
console.log(hours, ":", minutes, ":", seconds, AMPM);

＆＃13;

Answer 3

您可以像这样使用它：

var time = "12:30:49PM"
var hours = Number(time.match(/^(\d+)/)[1]);
var minutes = Number(time.match(/:(\d+)/)[1]);
var sec = Number(time.match(/:(\d+)\D+$/)[1]);
var AMPM = time.match(/([ap]m)$/i)[1];
console.log(hours);
console.log(minutes);
console.log(sec);
console.log(AMPM);

Answer 4

分开冒号和（P \ A）M部分

＆＃13;

var time  = "12:30:49PM";
var parts = time.split(/:|(\DM)/).filter(Boolean);

console.log(parts)

＆＃13;

Answer 5

var sec = Number(time.match(/:([0-9][0-9])/ig)[1].replace(":",""))

Answer 6

怎么样！

console.log(DateTimeFormat(new Date(), '`The Year is ${y} DateTime is: ${m}/${d}/${y} Time is: ${h}:${M}:${s}   `'))

function DateTimeFormat(dt, fmt)
{
    [y, m, d, h, M, s, ms] =  new 
    Date(dt).toLocaleString('UTC').match(/\d+/g)
    return eval(fmt)
}

如何正则表达式分割时间字符串

6 个答案: