我试图从下面的json过滤相同的颜色对象,每个颜色值包含两个值(颜色和数值)的组合,但我只想根据颜色进行过滤。
这是我试过的
var _ = require('underscore-plus');
var data = [{
"name": "jim",
"color": "blue 1",
"age": "22"
}, {
"name": "Sam",
"color": "blue 2",
"age": "33"
}, {
"name": "eddie",
"color": "green 1",
"age": "77"
},
{
"name": "Dheeraj",
"color": "blue 3",
"age": "25"
},
{
"name": "Suraj",
"color": "green 1",
"age": "25"
}
];
var result=_.groupBy(data,"color");
console.log(result)
结果应该是具有相同颜色的对象数组。
[{ "name": "jim", "color": "blue 1", "age": "22" },
{ "name": "Sam", "color": "blue 2", "age": "33" },
{ "name": "Dheeraj", "color": "blue 3", "age": "25" }]
和
[{ "name": "Suraj", "color": "green 1", "age": "25" },
{ "name": "eddie", "color": "green 1", "age": "77" }]
答案 0 :(得分:1)
您可以使用Array.prototype.reduce
对项目进行分组:
var data = [{
"name": "jim",
"color": "blue 1",
"age": "22"
}, {
"name": "Sam",
"color": "blue 2",
"age": "33"
}, {
"name": "eddie",
"color": "green 1",
"age": "77"
}, {
"name": "Dheeraj",
"color": "blue 3",
"age": "25"
}, {
"name": "Suraj",
"color": "green 1",
"age": "25"
}];
var result = data.reduce(function(grouped, obj) {
var key = obj.color.split(' ')[0]; // get the color from the key
grouped[key] = (grouped[key] || []).concat(obj); // use the existing array or create a new array, add the object to it, and assign it to the grouped object
return grouped; // return the grouped object
}, {});
console.log(result);

答案 1 :(得分:0)
您可以使用Jquery.grep()例如
var result = $.grep(data, function(n){ return n.color == "blue 3" })
答案 2 :(得分:0)
只需使用下划线文档here详细说明的groupBy
函数:
var result = _.groupBy(data, function(datum) { return datum.color; });
您需要提供一个要使用的函数,它将返回属性以对元素进行分组,在这种情况下为颜色。
如果您想要过滤,如问题中所述,您可以使用下划线filter
方法:
var blueOne = _.filter(data, function(datum){ return datum.color == 'blue 1'; });
答案 3 :(得分:0)
您可以按颜色分组。
var data = [{ "name": "jim", "color": "blue 1", "age": "22" }, { "name": "Sam", "color": "blue 2", "age": "33" }, { "name": "eddie", "color": "green 1", "age": "77" }, { "name": "Dheeraj", "color": "blue 3", "age": "25" }, { "name": "Suraj", "color": "green 1", "age": "25" }],
grouped = {},
colors;
data.forEach(function (a) {
var group = a.color.match(/^[a-z]+/i);
grouped[group] = grouped[group] || [];
grouped[group].push(a);
});
colors = Object.keys(grouped);
colors.forEach(function (color) {
console.log(color, grouped[color]);
});

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