Question

我对多个数据有一些问题。

我会在这里添加我的样本。

foreach (HotelPaxRoom c in h.PaxRoomSearchResults)
{
  int index = c.index;
  foreach (RoomCategory a in c.RoomCategories)
    {
             HRoom room = new HRoom();
             room.id = a.id;
             room.category = a.category;
             room.price = a.price;
             room.index = c.index;
    }
}

实际上PaxRoomSearchResults有数据列表。我将调用PaxRoomSearchResults作为A 在PaxRoomSearchResults里面有RoomCategories List，我将把RoomCategories称为B

我想使用这种逻辑读取数据。

A [0]与A [1]

的例子

A [0] .B [0]，A [1] .B [0] ---（A [0] index和B [0] first index）
A [0] .B [1]，A [1] .B [1]
A [0] .B [2]，A [1] .B [2]
A [0] .B [3]，A [1] .B [3]

A [0]对A [1]对A [2]

的例子

A [0] .B [0]，A [1] .B [0]，A [2] .B [0]
A [0] .B [1]，A [1] .B [0]，A [2] .B [1]
A [0] .B [2]，A [1] .B [0]，A [2] .B [2]
A [0] .B [3]，A [1] .B [0]，A [2] .B [3]

A [0] .B [0]，A [1] .B [1]，A [2] .B [0]
A [0] .B [1]，A [1] .B [1]，A [2] .B [1]
A [0] .B [2]，A [1] .B [1]，A [2] .B [2]
A [0] .B [3]，A [1] .B [1]，A [2] .B [3]

A [0] .B [0]，A [1] .B [2]，A [2] .B [0]
A [0] .B [1]，A [1] .B [2]，A [2] .B [1]
A [0] .B [2]，A [1] .B [2]，A [2] .B [2]
A [0] .B [3]，A [1] .B [2]，A [2] .B [3]

就像它明智一样.......... 实际上我不能用我的foreach来做到这一点。有没有更好的，更精确/快速的方法呢？

这总是应该用PaxRoomSearchResults第0个索引映射。然后是2，然后2就像明智一样。

请问您是否有任何问题重新解决我的问题。

实际上这个输出是我在xml反序列化后得到的。所以我会添加一小部分内容。这会让你有更好的理解

  <PaxRoomSearchResults>
                    <PaxRoom RoomIndex="1">
                        <RoomCategories>
                            <RoomCategory Id="xxx:rrrr:vvv:S7519:8456:115266">
                            </RoomCategory>
                        </RoomCategories>
                    </PaxRoom>
                    <PaxRoom RoomIndex="2">
                        <RoomCategories>
                            <RoomCategory Id="xxx:rrrr:vvv:S7519:8456:33689">
                            </RoomCategory>
                            <RoomCategory Id="xxx:rrrr:vvv:S7519:8456:33707">
                            </RoomCategory>
                            <RoomCategory Id="xxx:rrrr:vvv:S7519:8456:33695">
                            </RoomCategory>
                            <RoomCategory Id="xxx:rrrr:vvv:S7519:8456:115266">
                            </RoomCategory>
                        </RoomCategories>
                    </PaxRoom>

结果应该是这样的

我有这样的separete模型。

Public RoomGroup Class
  {
     public  int id {get;set;}
     public  List<RoomDetails> roomdetails{get;set;}
  }
  Public RoomDetails Class
  {
     public string roomcategoryID{get;set;}
     public decimal roomPrice{get;set;}
  }

输出就像这样

RoomGroup 1 roomcategoryID 001：AMB1：7736：S7519：8456：115266 roomcategoryID 001：AMB1：7736：S7519：8456：33689

RoomGroup 2 roomcategoryID 001：AMB1：7736：S7519：8456：115266 roomcategoryID 001：AMB1：7736：S7519：8456：33707

RoomGroup 3 roomcategoryID 001：AMB1：7736：S7519：8456：115266 roomcategoryID 001：AMB1：7736：S7519：8456：33695

RoomGroup 4 roomcategoryID 001：AMB1：7736：S7519：8456：115266 roomcategoryID 001：AMB1：7736：S7519：8456：115266

Answer 1

不完全确定你想要什么。也许这个：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            List<RoomGroup> roomGroup = new List<RoomGroup>() {
                new RoomGroup() {
                    id = 1,
                    roomdetails = new List<RoomDetails>() {
                        new RoomDetails() {
                            roomcategoryID = "001:AMB1:7736:S7519:8456:115266"
                        },
                        new RoomDetails() {
                            roomcategoryID = "001:AMB1:7736:S7519:8456:33689"
                        },
                    }
                },
                new RoomGroup() {
                    id = 2,
                    roomdetails = new List<RoomDetails>() {
                        new RoomDetails() {
                            roomcategoryID = "001:AMB1:7736:S7519:8456:115266"
                        },
                        new RoomDetails() {
                            roomcategoryID = "001:AMB1:7736:S7519:8456:33707"
                        },
                    }
                },
                new RoomGroup() {
                    id = 3,
                    roomdetails = new List<RoomDetails>() {
                        new RoomDetails() {
                            roomcategoryID = "001:AMB1:7736:S7519:8456:115266"
                        },
                        new RoomDetails() {
                            roomcategoryID = "001:AMB1:7736:S7519:8456:33695"
                        }
                    }
                },
                new RoomGroup() {
                    id = 4,
                    roomdetails = new List<RoomDetails>() {
                        new RoomDetails() {
                           roomcategoryID = "001:AMB1:7736:S7519:8456:115266"
                        },
                        new RoomDetails() {
                           roomcategoryID = "001:AMB1:7736:S7519:8456:115266"
                        }
                    }
                }
            };

            foreach (RoomGroup group in roomGroup)
            {
                string output = string.Format("RoomGroup {0} {1}", 
                        group.id.ToString(),
                        string.Join(" ", group.roomdetails.Select(x => "roomCategoryID " + x.roomcategoryID).ToArray())
                        );
                Console.WriteLine(output);
                Console.WriteLine();
            }
            Console.ReadLine();
        }
    }
    public class RoomGroup
    {
       public  int id {get;set;}
       public  List<RoomDetails> roomdetails{get;set;}
    }
    public class RoomDetails
    {
       public string roomcategoryID{get;set;}
       public decimal roomPrice{get;set;}
    }
}

地图列表数据（子列表数据）C＃

1 个答案: