首选方法：

Question

所以我把读取主机的输入变成了一个数组，它让我可以计算从$ Array看到的单词$ a中的单词的次数。但是Count ++并没有给我一个总数

   function Get-Sentence($a){
                if($a -contains $array) {
                   $Count++
                }
             else {
                   return 0
                }   
        }
        Write-Host "There are $count words"

        [array]$Array = @("a", "an", "the")
        [array]$a = Read-Host "Enter a long sentence from a story book or novel: ").split(" ")

Answer 1

首选方法：

准确计算多个子串出现次数的最简单方法可能是：

构造与任何一个子串相匹配的正则表达式模式
使用-split运算符拆分字符串
计算结果字符串数并减去1：

# Define the substrings and a sentence to test against
$Substrings = "a","an","the"
$Sentence   = "a long long sentence to test the -split approach, anticipating false positives"

# Construct the regex pattern
# The \b sequence ensures "word boundaries" on either side of a 
# match so that "a" wont match the a in "man" for example
$Pattern = "\b(?:{0})\b" -f ($Substrings -join '|')

# Split the string, count result and subtract 1
$Count = ($Sentence -split $Pattern).Count - 1

输出：

C:\> $Count
2

正如你所看到的，它将匹配并分裂为“a”和“the”，而不是“预期”中的“an”。

我会把这个转换成一个功能练习给读者

注意：如果您开始提供的不仅仅是简单的ASCII字符串作为输入，您可能希望在模式中使用它们之前将它们转义：

$Pattern = "\b(?:{0})\b" -f (($Substrings |ForEach-Object {[regex]::Escape($_)}) -join '|')

天真的方法：

如果你对正则表达式感到不舒服，你可以假设两个空格之间的任何东西都是“一个单词”（就像在你的原始例子中一样），然后遍历句子中的单词并检查是否数组包含有问题的字（不是相反）：

$Substrings = "a","an","the" $Sentence = (Read-Host "Enter a long sentence from a story book or novel: ").Split(" ") $Counter = 0 foreach($Word in $Sentence){ if($Substrings -contains $Word){ $Counter++ } }

作为suggested by Jeroen Mostert，您还可以使用HashTable。通过这种方式，您可以跟踪每个单词的出现次数，而不仅仅是总计数：

$Substrings = "a","an","the" $Sentence = (Read-Host "Enter a long sentence from a story book or novel: ").Split(" ") # Create hashtable from substrings $Dictionary = @{} $Substrings |ForEach-Object { $Dictionary[$_] = 0 } foreach($Word in $Sentence){ if($Dictionary.ContainsKey($Word)){ $Dictionary[$Word]++ } } $Dictionary

Answer 2

public function deleteAction($id)
{
  $em = $this->getDoctrine()->getManager();

  $gig = $this->getDoctrine()
      ->getRepository('GoetzBundle\Entity\Gig')
      ->findOneById($id);

  ...

  foreach ($gig->getArtists() as $artist) {
      $gig->removeArtist($artist);
  }

  $em->persist($gig);
  $em->flush();

  ...
}

Powershell - 如何计算数组中的计数出现次数

2 个答案:

首选方法：

天真的方法：