Question

mongodb全新，我正在尝试以我需要的格式查询某些报告。

以下是我的资产收集的结果：

db.getCollection('Asset').find({})

结果：

    /* 1 */
{
    "_id" : ObjectId("58176238f23ee4040a48846c"),
    "AssetTypeId" : "58176225f23ee4040a48846b",
    "AssetTypeName" : "Chairs",
    "Fields" : [ 
        {
            "_id" : "5770ae6cf500fd7675c234c5",
            "Title" : "Asset Name",
            "Value" : "Fancy Chair"
        }, 
        {
            "_id" : "576b7593f500fd7675c234b9",
            "Title" : "Status",
            "Value" : "Missing"
        }, 
        {
            "_id" : "57b2b52b31f7c7d80db34a23",
            "Title" : "Location",
            "Value" : "Office")
        }
    ]
}

/* 2 */
{
    "_id" : ObjectId("5817638ff23ee4040a48846e"),
    "AssetTypeId" : "58176225f23ee4040a48846b",
    "AssetTypeName" : "Chairs",
    "Fields" : [ 
        {
            "_id" : "5770ae6cf500fd7675c234c5",
            "Title" : "Asset Name",
            "Value" : "Basic Chair"
        },  
        {
            "_id" : "576b7593f500fd7675c234b9",
            "Title" : "Status",
            "Value" : "Stores"
        },
        {
            "_id" : "57b2b52b31f7c7d80db34a23",
            "Title" : "Location",
            "Value" : "Home")
        }
    ]
}

/* 3 */
{
    "_id" : ObjectId("581767f3f23ee4040a488471"),
    "AssetTypeId" : "5817678ff23ee4040a488470",
    "AssetTypeName" : "Table",
    "Fields" : [ 
        {
            "_id" : "5770ae6cf500fd7675c234c5",
            "Title" : "Asset Name",
            "Value" : "Fancy Table"
        },
        {
            "_id" : "576b7593f500fd7675c234b9",
            "Title" : "Status",
            "Value" : "Active"
        }, 
        {
            "_id" : "57b2b52b31f7c7d80db34a23",
            "Title" : "Location",
            "Value" : "Office")
        }
    ]
}

这是我试图从查询中获得的最终结果：

[
{"Asset Name":"Fancy Chair", "Status":"Missing","Location":"Office","AssetTypeName":"Chairs"},
{"Asset Name":"Basic Chair", "Status":"Stores","Location":"Office","AssetTypeName":"Chairs"},
{"Asset Name":"Fancy Table", "Status":"Active","Location":"Office","AssetTypeName":"Table"}
]

Answer 1

您只需要通过迭代结果并创建新的对象数组，将mongodb 资产结果转换为首选格式：

function processAssets(assets){
   var results = [];
   for (var i=0;i<assets.length;i++){
      var asset = assets[i];
      var result = {AssetTypeName: asset.AssetTypeName};
      //AssetTypeName is not in the Fields array
      for (var f=0;f<asset.Fields.length;f++){
         var field = asset.Fields[f];
         result[field.Title] = field.Value;
         //this will make result['Asset Name'] = 'Fancy Chair', etc
      }
      results.push(result);
   } 
   return results;
}

更多的mongodb方法是使用cursor.map方法：

db.Asset.find().map(function(asset){
    var result = {AssetTypeName: asset.AssetTypeName};
    for (var f=0;f<asset.Fields.length;f++){
       var field = asset.Fields[f];
       result[field.Title] = field.Value;
    }
    return result;
});

如何查询mongo以我想要的格式显示结果？

1 个答案: