Question

我有这个功能：

 charCtrl.loadDataFromToMonth= function (from,to,year) {
var url = servername+'admin/dashboard/getIncidentDepartByMonthFromTo/'+from+'/'+to+'/'+year;
//alert(url);
function onSuccess(response) {
  console.log("+++++getIncidentDepartByMonthFromTo SUCCESS++++++");

  if (response.data.success != false) {

    $scope.payloadgetIncidentDepartByMonthFromTo = response.data.data;

    var getIncidentDepartByMonthFromTo= $scope.payloadgetIncidentDepartByMonthFromTo;
    // alert('dddd'+JSON.stringify(loadedDataByMission));
    $scope.labelsf = [];
    $scope.qsd = [];
    $scope.dataf = [];
    getIncidentDepartByMonthFromTo.forEach(function(data) {
      var monthNumber=$filter('date')(data.la_date, "MM");
      $scope.labelsf.push($filter('monthName')(monthNumber));
      $scope.dataf.push(data.number);
      $scope.qsd.push('ff','ff','ff');
    //alert($scope.labelsf );
    });
    //alert( $scope.dataf );
   charCtrl.loadDataFromToMonthArrivee(from,to,year);
  } else {
    alert("failure");
  }
  //  $scope.stopSpin('spinner-0');
};

function onError(response) {
  console.log("-------getIncidentDepartByMonthFromTo FAILED-------");
  //$scope.stopSpin('spinner-0');
  console.log(response.data);
  console.log("Inside getIncidentDepartByMonthFromTo error condition...");
};

//----MAKE AJAX REQUEST CALL to GET DATA----
 ajaxServicess.getData(url,username,password, 'GET', '').then(onSuccess, onError);

 };

此函数返回示例：$ scope.dataf = ['45'，'48'，'255'];

我有第二个功能，顺便说一下它的功能相同，但它从其他Rest服务获取数据：

charCtrl.loadDataFromToMonthArrivee= function (from,to,year) {
var url = servername+'admin/dashboard/getIncidentArriveeByMonthFromTo/'+from+'/'+to+'/'+year;
//alert(url);
function onSuccess(response) {
  console.log("+++++getIncidentDepartByMonthFromTo SUCCESS++++++");

  if (response.data.success != false) {

    $scope.payloadgetIncidentArriveeByMonthFromTo = response.data.data;

    var getIncidentArriveeByMonthFromTo= $scope.payloadgetIncidentArriveeByMonthFromTo;
    // alert('dddd'+JSON.stringify(loadedDataByMission));
    $scope.labelsf = [];
    $scope.qsd = [];
    $scope.dataf = [];
    getIncidentArriveeByMonthFromTo.forEach(function(data) {
      var monthNumber=$filter('date')(data.la_date, "MM");
      $scope.labelsf.push($filter('monthName')(monthNumber));
      $scope.dataf.push(data.number);
      //$scope.qsd.push('ff','ff','ff');
      //alert($scope.labelsf );
    });
    alert('aqsz'+$scope.dataf );
  } else {
    alert("failure");
  }
  //  $scope.stopSpin('spinner-0');
};

function onError(response) {
  console.log("-------getIncidentDepartByMonthFromTo FAILED-------");
  //$scope.stopSpin('spinner-0');
  console.log(response.data);
  console.log("Inside getIncidentDepartByMonthFromTo error condition...");
};

//----MAKE AJAX REQUEST CALL to GET DATA----
ajaxServicess.getData(url,username,password, 'GET', '').then(onSuccess, onError);

  };

此函数返回示例：$ scope.dataf = ['69'，'50'，'96'];

我的问题是：有没有办法在第一个函数中声明第二个函数并获得如下结果：此函数返回例如：$ scope.dataf = [['45'，'48'，'255']，['69'，'50'，'96']];

Answer 1

我会使用promises等待第二个调用来响应并更新函数作用域中的变量（兄弟到函数）。像这样：

var aggregate = [];

charCtrl.loadDataFromToMonth()
.then(function(resp){
  return new Promise(resolve, reject){

    aggregate.push(resp.data); // push the response from the first call

    charCtrl.loadDataFromToMonthArrivee()
    .then(function(resp) {
      aggregate.push(resp.data); // push the result from the second call
      resolve(resp)
    })
  }
})
.then(function(resp){

  console.log(aggregate); // should have both results

})

或者更好的是，您可以使用Promise.all（https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all）

在另一个函数内声明一个函数

1 个答案: