Question

我对OOP很新，所以我遇到了一个问题

我创建了一个班级

/modules/template/02.02.01.10-SNAPSHOT/templates/base/navbar2/navbarlinks-lang

然后是一个对象

class Lesson {
        function Lesson( $title, $sample ) {
            $this->title = $title;
            $this->sample = $sample;
        }
 }

当我试图访问对象的属性时

$title = 'title';
$sample = false;
$lesson = new Lesson( $title, $sample );

我收到此错误消息

＆＃34;脚本试图执行方法或访问某个属性不完整的对象...＆＃34;

Answer 1

您的属性尚未定义。尝试在类声明的顶部添加它们。

class Lesson {
        public $title = '';
        public $sample = '';
        public function Lesson( $title, $sample ) {
            $this->title = $title;
            $this->sample = $sample;
        }
 }

构造函数语法也取决于php的含义。如果你是＆gt; 5.3.3你应该使用__construct()

class Lesson {
        public $title = '';
        public $sample = '';
        function __construct( $title, $sample ) {
            $this->title = $title;
            $this->sample = $sample;
        }
 }

Answer 2

您需要将function Lesson更改为function __construct才能在创建时传递这些值。

class Lesson {
    function __construct( $title, $sample ) {
        $this->title = $title;
        $this->sample = $sample;
    }
 }

否则，您必须像这样创建它：

$lesson = new Lesson();
$lesson->Lesson($title, $sample);
echo $lesson->title;

对象的属性不可访问

2 个答案: