我在Excel 2010中使用此宏来查找和替换单词而不会丢失单元格格式(例如,某些单词以粗体显示,有些单词以斜体显示,因此此宏只确保单元格在替换单词时保持相同的格式) :
' Replacement of characters in the range(s) with storing of original Font
' Arguments:
' Rng - range for replacement
' FindText - string being searched for
' ReplaceText - replacement string
' MatchCase - [False]/True, True to make the search case sensitive
Sub CharactersReplace(Rng As Range, FindText As String, ReplaceText As String, Optional MatchCase As Boolean)
Dim i&, j&, jj&, k&, v$, m&, x As Range
j = Len(FindText)
jj = Len(ReplaceText)
If Not MatchCase Then m = 1
For Each x In Rng.Cells
If VarType(x) = vbString Then
k = 0
i = 1
With x
v = .Value
While i <= Len(v) - j + 1
If StrComp(Mid$(v, i, j), FindText, m) = 0 Then
.Characters(i + k, j).Insert ReplaceText
k = k + jj - j
i = i + j
Else
i = i + 1
End If
Wend
End With
End If
Next
End Sub
' Testing subroutine
Sub Test_CharactersReplace()
CharactersReplace Range("A743:F764"), "Replace This", "With This", True
End Sub
当我运行宏时,存在一个问题,即当单元格超过255个字符时代码不起作用。
我一直在网上查找,但没有真正的解决方案!有谁知道如何解决这个问题?
答案 0 :(得分:0)
EDIT ::
这不是一个简单的解决方案,但基本上你需要做的是:
我设法创造了一些有用的东西,它有点长,但我不知道其他任何方式。
另外,请注意,这只取/替换字体样式(粗体,斜体等) - 它不会复制任何颜色,大小,字体等的更改。通过添加更多数组,可以很容易地合并它们并在现有循环中设置/修改它们的值。
Public Sub RunTextChange()
Dim x as Range
For each x in Range("A743:F764")
Call TextChange(x, "Replace This", "With This")
Next x
End Sub
Public Sub textchange(TargetCell As Range, FindTxt As String, ReplaceTxt As String)
''''Variables for text and length
Dim text1 As Variant: Dim text_length As Long
text1 = TargetCell.Value: text_length = Len(text1)
'variables for lengths of find/replace strings and difference
Dim strdiff As Long: Dim ftlen As Long: Dim rtlen As Long
ftlen = Len(FindTxt): rtlen = Len(ReplaceTxt): strdiff = rtlen - ftlen
'font arrays and loop integers
Dim fonts1 As Variant: Dim x As Long: Dim z As Long
Dim fonts2 As Variant
'set font array to length of string
ReDim fonts1(1 To text_length) As Variant
'make font array to correspond to the fontstyle of each character in the cell
For x = 1 To text_length
fonts1(x) = TargetCell.Characters(Start:=x, Length:=1).Font.FontStyle
Next x
'detect first instance of find text- if not present, exit sub
z = InStr(text1, FindTxt)
If z = 0 Then Exit Sub
'continue loop as long as there are more instances of find string
Do While z > 0
'replace each instance of find string in turn (rather than all at once)
text1 = Left(text1, z - 1) & Replace(text1, FindTxt, ReplaceTxt, z, 1)
'if no difference between find and replace string lengths, there is no need to amend the fonts array
If Not strdiff = 0 Then
'otherwise, expand fonts array and push values forward (or back, if the replace string is shorter)
fonts2 = fonts1
ReDim Preserve fonts1(1 To text_length + strdiff) As Variant
For x = z + ftlen To text_length
fonts1(x + strdiff) = fonts2(x)
Next x
'set all the letters in the replacement string to the same font as the first letter in the find string
For x = z To z + rtlen - 1
fonts1(x) = fonts2(z)
Next x
End If
'change text_length to reflect new length of string
text_length = Len(text1)
'change z to search for next instance of find string - if none, will exit loop
z = InStr(z + rtlen, text1, FindTxt)
Loop
'change cell Value to new string
TargetCell.Value = text1
'change all characters to new font styles
For x = 1 To text_length
TargetCell.Characters(Start:=x, Length:=1).Font.FontStyle = fonts1(x)
Next x
End Sub