Question

此子例程检查每一行的最低值。我想知道这个值在哪一列。我该如何处理？这是我到目前为止所得到的：

Sub LowCol()
    Dim iAnz As Long
    Dim myrange As Range
    Dim rCell As Range
    Dim iLevel As Long
    Dim i As Long
    Dim j As Long
    Dim iPos As Long
    Dim dMin As Double
    iAnz = Worksheets("v1").Cells(6, 3).Value    'amount of columns
    iLevel = Worksheets("b1").Cells(2, 2).Value    'amount of rows

    For i = 0 To iLevel
        Set myrange = Worksheets("b1").Range(Cells(5 + i, 2 + iAnz + 1), Cells(5 + i, 2 + iAnz + iAnz + 1))
        dMin = Application.WorksheetFunction.Min(myrange)
        Set rCell = myrange.Find(What:=dMin, LookIn:=xlValues, _
                                 LookAt:=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
                                 MatchCase:=False, SearchFormat:=False)
        iPos = CLng(rCell.Column)    'this line is obviously not working. How to fix?
        Worksheets("b1").Cells(5 + i, 2 + iAnz + iAnz + 1).Value = iPos
    Next i
End Sub

Answer 1

您不需要VBA来获取MIN值的列数。只需使用MATCH的公式，例如：

=MATCH(MIN(A1:G1);A1:G1;0)

Answer 2

这并不像Min函数一样快，但除非您使用大型数据集，否则它不会产生太大的影响。

Function getMinValueColumn(Target As Range) As Long
    Dim r As Range, rMin As Range

    If Target Is Nothing Then Exit Function
    For Each r In Target
        If r.Value <> vbNullString Then
            If rMin Is Nothing Then Set rMin = r
            If r.Value < rMin.Value Then Set rMin = r
        End If
    Next
    If Not rMin Is Nothing Then getMinValueColumn = rMin.Column
End Function

VBA：如何确定具有最低行值的列？

2 个答案: