SQLFiddle

Question

我有这样的表

表1

nid  |  name 
3      john

表2

tid | address  | fkey_id
56      city       3
57     street      3

结果

name  | address

约翰城街

我怎样才能得到这样的结果我尝试下面的代码

SELECT name,address
FROM tbl_name
INNER JOIN tbl_address
    ON tbl_name.nid = tbl_address.fkey_id';

结果我得到了json

{
    "name": "john",
    "address": "city"
},
{
    "name": "john",
    "address": "street"
},

但我希望像这样的json结果

{
    "name": "john",
    "address": "street,city"
}

请帮帮我

Answer 1

您需要的实际概念是GROUP_CONCAT MySQL。

您需要的最终查询是

SELECT t1.name,t2.final_address FROM tbl_name t1 INNER JOIN ( SELECT fkey_id,GROUP_CONCAT(address) as final_address FROM tbl_address GROUP BY fkey_id ) t2 ON t1.nid = t2.fkey_id

Answer 2

一种选择是使用GROUP_CONCAT：

SELECT t1.name, GROUP_CONCAT(t2.address) AS address
FROM tbl_name t1
INNER JOIN tbl_address t2
    ON t1.nid = t2.fkey_id
GROUP BY t1.name

在这里演示：

如何在单个字段中将相同的forgin键值值数据作为单个表数据进行检索

2 个答案:

SQLFiddle