Question

所以我使用cURL和PHP从JSON文件中检索一些数据。 cURL脚本返回如下内容：https://s4.postimg.org/43svl8rot/image.png

我正在使用这个PHP脚本：

// Generated by curl-to-PHP: http://incarnate.github.io/curl-to-php/
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, "https://test.pt/api/objgroupinfo/16Jcr05g37KpLklz");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET");


$headers = array();
$headers[] = "X-Apikey: xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); 

$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}
curl_close ($ch);






// Generated by curl-to-PHP: http://incarnate.github.io/curl-to-php/
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, "https://test.pt/api/dataout/IAfhAfTIUZrCje5q.json");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET");


$headers = array();
$headers[] = "X-Apikey: xxxxxxxxxxxxxxxxxxxxxx";
$headers[] = "X-Startdate: 2016-10-01 00:00:00";
$headers[] = "X-Enddate: 2016-10-10 15:00:00";
$headers[] = "X-Channelnum: 0";
$headers[] = "X-Reclimit: 200";
$headers[] = "User-Agent: test/1.0";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); 

$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}


$json = json_decode($result,true);
print_R($json);


curl_close ($ch);

有人可以帮助我如何将这些数据转换为我可以使用的对象或数组吗？我需要访问这些数据以图形方式显示

Answer 1

json_decode会将JSON编码的字符串转换为PHP变量，请参阅json_decode。看起来您的代码已经在执行此操作。

使用来自cURL的数据创建对象

1 个答案: