我试图通过SQL SUM运算符显示和过滤数据。 我有2名员工和部门。表员工包含department_id归档和工资。我需要显示每个部门的所有部门和总工资。 我遵循了这个guide,但GridView不显示任何数据。 这是行动:
public function actionIndex()
{
$searchModel = new DepartmentFrontendSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index',
[
'dataProvider' => $dataProvider,
'searchModel' => $searchModel,
]
);
}
型号:
class DepartmentFrontendSearch extends DepartmentFrontend
public $employee_count;
public $salary;
public function rules() {
return [
[['employee_count','salary','name'], 'safe']
];
}
public function search($params) {
$query = DepartmentFrontend::find();
$subQuery = Employee::find()
->select('department_id, SUM(salary) as salary_amount')
->groupBy('department_id');
$query->leftJoin(['salarySum' => $subQuery], 'salarySum.department_id = id');
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->setSort([
'attributes' => [
'name',
'salary'
]
]);
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere(['like', 'name', $this->name]);
$query->andWhere(['salarySum.salary_amount' => $this->salary]);
return $dataProvider;
}
GRID:
echo GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'salary_amount',
'employee_count',
'name',
],
]);
那么,有谁能告诉我我做错了什么?
答案 0 :(得分:0)
如果你需要一个别名salary_amount的过滤器,你应该为此添加一个特定的var(事实上salary_amount是sum(salary)的别名,var $ salary是没用的)
public $employee_count;
public $salary;
public $salary_amount;
否则也使用薪水作为别名
您正在使用的过滤器
$query->andWhere(['salarySum.salary_amount' => $this->salary]);
但salary_amount是汇总的结果,因此您应该使用having(SUM(salary) = $this->salary_amount)
$query->having('SUM(salary) = ' . $this->salary_amount);