Question

我正在学习MySQL课程，我正在学习如何在用户输入代码（电子邮件和密码）中将脚本中的信息放入phpMyAdmin的数据库中。我似乎无法让它发挥作用？当我通过错误检查程序时，我的代码没有任何错误。我也是PHP和MySQL的新手。我知道它可以找到数据库，因为我可以更新现有数据。

<?php

$link = mysqli_connect("host", "username", "password", "username");

if (mysqli_connect_error()) {

    die ("There was an error connecting to the database");

} 

$query = "INSERT INTO `users` (`email`, `password`) VALUES('email', 'password')"; 

mysqli_query($link, $query);

$query = "SELECT * FROM users";

if ($result = mysqli_query($link, $query)) {

 $row = mysqli_fetch_array($result);

 echo "Your email is ".$row[1]." and your password is ".$row[2];

}

?>

Answer 1

创建了精致版本。核实。

   <?php

    $link = mysqli_connect("host", "username", "password", "username");

    if (mysqli_connect_error()) {

        die ("There was an error connecting to the database");

    } 

    $query = "INSERT INTO `users` (`email`, `password`) VALUES('email', 'password')"; 

    $result = mysqli_query($link, $query);
    if($result != false)
    {
        echo "The record has been successfully inserted.<br>";
    }
    else
    {
        echo "Error Occured in the INSERT query.<br>Error : ".mysqli_error($link);
    }

    $query = "SELECT * FROM users";
    $result = mysqli_query($link, $query);
    if($result != false)
    {
        echo mysqli_num_rows($result)." Records found.<br>";
        while($rows = mysqli_fetch_array($result))
        {
            echo $rows["email"]."<br>";
        }
    }
    else
    {
        echo "Error Occured in the SELECT query.<br>Error : ".mysqli_error($link);
    }


    mysqli_close($link);

    ?>

Answer 2

<强>更新

事实证明我没有设置auto_increment设置，因此我设置数据库的方式不正确！他在我正在经历的教程中设置了另一个数据库，我发现他正在做的事情。感谢大家帮助我解决问题的努力！

Answer 3

为什么你不尝试用php接收它们？

简单地制作

$email= $POST['email']
$password= $POST['password']

将查询更改为

$query = "INSERT INTO `users` (`email`, `password`) VALUES(" .$email. ", ". $password.")";

MySQL进入数据库不起作用

3 个答案: