我正在画一段正弦波:
let width = rect.width
let height = rect.height
let origin = CGPoint(x: width * (1 - graphWidth) / 2, y: height * 0.50)
let path = UIBezierPath()
path.move(to: origin)
for angle in stride(from: 5.0, through: 360.0, by: 5.0) {
let x = origin.x + CGFloat(angle/360.0) * width * graphWidth
let y = origin.y - CGFloat(sin(angle/180.0 * Double.pi)) * height * amplitude
path.addLine(to: CGPoint(x: x, y: y))
}
Globals.sharedInstance.palleteGlowGreen.setStroke()
path.stroke()
我将如何:
答案 0 :(得分:5)
只需将angle
乘以periods
:
@IBDesignable
class SineWaveView: UIView {
@IBInspectable
var graphWidth: CGFloat = 0.90 { didSet { setNeedsDisplay() } }
@IBInspectable
var amplitude: CGFloat = 0.20 { didSet { setNeedsDisplay() } }
@IBInspectable
var periods: CGFloat = 1.0 { didSet { setNeedsDisplay() } }
override func draw(_ rect: CGRect) {
let width = bounds.width
let height = bounds.height
let origin = CGPoint(x: width * (1 - graphWidth) / 2, y: height * 0.50)
let path = UIBezierPath()
path.move(to: origin)
for angle in stride(from: 5.0, through: 360.0 * periods, by: 5.0) {
let x = origin.x + angle/(360.0 * periods) * width * graphWidth
let y = origin.y - sin(angle/180.0 * .pi) * height * amplitude
path.addLine(to: CGPoint(x: x, y: y))
}
Globals.sharedInstance.palleteGlowGreen.setStroke()
path.stroke()
}
}
顺便说一句,通过periods
来电setNeedsDisplay
进行更改,这意味着当您更新periods
时,图表会自动重新绘制。
而且,不是迭代度数,而是将所有东西都转换回弧度,我可能只是保持弧度:
override func draw(_ rect: CGRect) {
let width = bounds.width
let height = bounds.height
let origin = CGPoint(x: width * (1 - graphWidth) / 2, y: height * 0.50)
let maxAngle: CGFloat = 2 * .pi * periods
let iterations = Int(min(1000, 100 * periods))
let point = { (angle: CGFloat) -> CGPoint in
let x = origin.x + angle/maxAngle * width * self.graphWidth
let y = origin.y - sin(angle) * height * self.amplitude
return CGPoint(x: x, y: y)
}
let path = UIBezierPath()
path.move(to: point(0))
for i in 1 ... iterations {
path.addLine(to: point(maxAngle * CGFloat(i) / CGFloat(iterations)))
}
Globals.sharedInstance.palleteGlowGreen.setStroke()
path.stroke()
}