我正在创建一个在线银行。登录时,它为该用户创建了一个会话。用户可以选择单击不同的事务类型。因此,当用户单击打开帐户按钮时,它将转到openAccount.jsp页面。我还在openAccount.jsp中有一个用户名,姓和电子邮件的表单。当用户点击打开帐户按钮并重定向到openAccount.jsp时,我希望从数据库预先填写表单。我不知道怎么样?到目前为止,这是我的代码:
家庭page.jsp
<div class="col-md-4">
<form name = "OpenAccount" action="open-account.jsp" id="openaccount">
<p>
<button type="submit" class="btn btn-primary btn-lg">Open Account</button>
</p>
</form>
</div>
开account.jsp
<!DOCTYPE html>
<html>
<head>
<title>Open Account</title>
</head>
<body>
<h3>Please fill in the details</h3>
<form name="predifinedFields">
First Name: <input type="text" name="firstname" value= <%= request.getAttribute("firstname") %> > <br/><br/>
Last Name: <input type="text" name="lastname" value= <%= request.getAttribute("lastname") %>> <br/><br/>
Email: <input type="text" name="email" value= <%= request.getAttribute("email") %>> <br/><br/>
</form>
<form name="openAccount" action="OpenAccount" method="POST">
Select the type of account:
<select name="accounttype">
<option>Checking</option>
<option>Saving</option>
</select> <br/><br/>
Initial Deposit: $<input type="text" name="deposit"> <br/><br/>
Please check the box if everything above is complete:
Agree <input type="radio" name="agree" value="Agree">
Disagree <input type="radio" name="agree" value="Disagree">
<br/><br/>
<input type="submit" value="submit" name="Submit">
</form>
</body>
</html>
OpenAccount.java
public class OpenAccount extends HttpServlet
{
private static final long serialVersionUID = 1L;
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
String username = "";
HttpSession session = request.getSession(false);
if(session != null)
{
username = (String) session.getAttribute("username");
Users users = new Users();
users = DBConnection.getUsers(username);
request.setAttribute("firstname", users.getFirstName());
request.setAttribute("lastname", users.getLastName());
request.setAttribute("email", users.getEmail());
//request.setAttribute("username", users.getUsername());
}
// String firstName = (String) request.getParameter("firstname");
// String lastname = (String) request.getParameter("lastname");
String email = (String) request.getParameter("email");
String accountType = (String) request.getParameter("accounttype");
String accept = (String) request.getParameter("agree");
String deposit = (String) request.getParameter("deposit");
if(accept.equals("Agree"))
{
if(accountType.equals("Checking"))
{
DBConnection.newCheckingAccount(email, deposit);
RequestDispatcher dispatcher = request.getRequestDispatcher("home-page.jsp");
dispatcher.forward(request, response);
}
else if(accountType.equals("Saving"))
{
DBConnection.newSavingAccount(email, deposit);
RequestDispatcher dispatcher = request.getRequestDispatcher("home-page.jsp");
dispatcher.forward(request, response);
}
}
else
{
System.out.println("Please modify the changes");
RequestDispatcher dispatcher = request.getRequestDispatcher("open-account.jsp");
dispatcher.forward(request, response);
}
}
}
Database.java
public static Users getUsers(String username)
{
Users user = new Users();
try
{
DBConnection.connectToDB();
String query = "SELECT * FROM userlogin where username=?";
stmt = DBConnection.conn.prepareStatement(query);
stmt.setString(1,username);
ResultSet rs = stmt.executeQuery();
while(rs.next())
{
user.setFirstName(rs.getString("firstname"));
user.setLastName(rs.getString("lastname"));
user.setEmail(rs.getString("email"));
user.setUsername(rs.getString("username"));
user.setPassword(rs.getString("password"));
}
}
catch(Exception e)
{
System.out.println(e);
}
return user;
}
答案 0 :(得分:0)
在你的情况下(基本servlet),你应该遵循这个逻辑:
- &gt;浏览器
- &gt; servlet,用于将所需的数据从数据库加载并准备到请求属性中,并最终转发到open-account.jsp
- &gt; open-account.jsp
使用请求属性动态呈现从数据库中检索到的数据字段。
对于其他用例,请尝试保持这个简单的逻辑:
- &gt;浏览器
- &gt; servlet处理....
- &gt; jsp渲染....
home-page.jsp
中的表单应该发布到servlet(控制器):
<div class="col-md-4">
<form name = "OpenAccount" action="/OpenAccount" id="openaccount">
<p>
<button type="submit" class="btn btn-primary btn-lg">Open Account</button>
</p>
</form>
</div>
您应该将OpenAccount
重命名为OpenAccountServlet
(保持约定更好)并正确配置servlet
中OpenAccountServlet
的{{1}}(或带注释) 。
如果您使用web.xml
文件进行servlet配置,则上一个web.xml
(jsp
)中发布的网址应与action="/OpenAccount"
前锋应该这样做:
<url-pattern>/OpenAccount</url-pattern>