我强烈地感到这是一个愚蠢的错误,我不知道怎么也看不到它。我试图在邮件的视图中使用这段代码。
<p><%= link_to 'here', unsubscribe_path(:email => "a@b.com") %></p>
我在路线文件中定义了一条命名路线:
map.unsubscribe '/unsubscribe', :controller => :users, :action => :unsubscribe
所以当我发送电子邮件时,这是我得到的链接:
http://b.comonly_pathtruecontrollerusersactionunsubscribe/
有什么想法吗?谢谢 !
修改
以下是观点:
<html>
<body>
<p>
Hi, <br />
You have an alert for : <%= @alert.name %>. <br />
Here is some brief information about it: <br />
<%= @alert.details %><br /><br />
<br />Thank You,<br />
</p>
<p>
Click <p><%= link_to 'here', unsubscribe_path(:email => "a@b.com") %></p> to unsubscribe</p>
</body>
</html>
这是邮寄者:
class Alert < ActionMailer::Base
def send(alert, email)
@subject = "hi"
@recipients = "xyz@mail.com"
@from = "xyz@mail.com"
@sent_on = Time.now
@content_type = "text/html"
@alert = alert
@email = email
end
端
答案 0 :(得分:1)
以下是一个工作模板的示例,我不能确定为什么你的工作模板无效但尝试在通知程序中生成网址。
# notifier
def new_message_email(response)
I18n.locale = response.recipient.language
subject I18n.t(:you_have_received_new_message_from_sender, :sender => response.sender.login)
from "info@domain.com"
recipients response.recipient.email
content_type "text/html"
sent_on Time.now
body :sender_login => response.sender.login, :recipient_login => response.recipient.login
end
#template
= word_wrap "Hi #{@recipient_login}."
= word_wrap ""
%p
= word_wrap "You have received a new personal message from #{@sender_login}.", :line_width => 60
= word_wrap "Click #{link_to 'here', account_inbox_url} to view your domain.com message inbox.", :line_width => 60
= word_wrap "If the above URL does not work try copying and pasting it into your browser. If you continue to have problems, please feel free to contact us at support@domain.com.", :line_width => 60
您需要生成网址,而不是路径。
eg:
account_path => /account
account_url => http://domain.com/account
编辑: 这应该有效:
#notifier
body :unsubscribe_url => unsubscribe_url(:email => "a@b.com")
#template
= word_wrap "Click #{@unsubscribe_url} to unsubscribe.", :line_width => 60
(参见上面的示例,了解这一切是如何组合在一起的)
答案 1 :(得分:1)
这个unsubscribe_url(或_path)是否可以在任何其他视图中使用?
返回的值看起来像是由转换为String的Hash创建的。尝试在“link_to()”返回的对象上调用.inspect - 也许会有一些线索?
也许在代码中某处重新定义了link_to方法?使用“grep def。* link_to” - 也许会有一些线索?
在此及以后的情况下,测试可能会有用。这是一个例子(但这是我在rails 1中使用的,但我希望你的rails版本没有太大差异。)
def test_routing
assert_routing '/unsubscribe', {:controller => 'user', :action => 'unsubscribe'}
assert_recognizes Hash[:controller => 'user', :action => 'unsubscribe'],
{:path=>'/unsubscribe', :method => :get},
{"email"=>"a@example.com"}
# ..and so on
end