我从数据库中提取数据然后在我的html页面上显示它。我曾经认为我的代码可以正常工作，它确实可以获取数据并将其放入变量中。当尝试将变量注入html标记时，它会崩溃。我也可能错误地认为，通过将我的html标签放在php foreach循环中，它会动态创建所需的所有标签，具体取决于返回的行数。我需要foreach，因为数据是一个数组，所以我需要通过数组来查看每条记录。
我已将此代码放在我的body标签中，我希望放置这些元素。
PHP函数在body标签上方的部分中。
<?php
function db_connect() {
// Define connection as a static variable, to avoid connecting more than once
static $connection;
// Try and connect to the database, if a connection has not been established yet
if(!isset($connection)) {
// Load configuration as an array. Use the actual location of your configuration file
$config = parse_ini_file('\assets\con_config.ini');
$connection = mysqli_connect('localhost',$config['username'],$config['password'],$config['dbname']);
}
// If connection was not successful, handle the error
if($connection === false) {
// Handle error - notify administrator, log to a file, show an error screen, etc.
return mysqli_connect_error();
}
return $connection;
}
function db_query($query) {
// Connect to the database
$connection = db_connect();
// Query the database
$result = mysqli_query($connection,$query);
return $result;
}
function db_select($query) {
$rows = array();
$result = db_query($query);
// If query failed, return `false`
if($result === false) {
return false;
}
// If query was successful, retrieve all the rows into an array
while ($row = mysqli_fetch_assoc($result)) {
$rows[] = $row;
}
return $rows;
}
$rows = db_select("select CONCAT_WS(' ', fname, mname, lname) as author_name, title, image_location, rating, review, (Select mid(date_reviewed,1,2) from reviews where reviews.book_id = books.id) as day, (Select mid(date_reviewed,4,3) from reviews where reviews.book_id = books.id) as month, (Select mid(date_reviewed,8,2) from reviews where reviews.book_id = books.id) as year, sellers_site, twitter_site, fb_site, twitter_id, fb_id, genre from authors, books, book_genre, book_link, reviews, social_media where books.author_id = authors.id and book_genre.book_id = books.id and book_link.book_id = books.id and reviews.book_id = books.id and social_media.author_id = authors.id group by ireviews.reviews.date_reviewed ASC");
if($rows === false) {
$error = db_error();
// Handle error - inform administrator, log to file, show error page, etc.
}
//foreach($rows as $value){
//echo $value['author_name'] . "<br />\n";
//echo $value['title'] . "<br />\n";
//echo $value['rating'] . "<br />\n";
//}
?>
<? php foreach($rows as $value); ?>
用于显示返回数据的HTML部分。
<? php foreach($rows as $value); ?>
<div class="block">
<div class="row">
<div class="col-md-4 col-md-8">
<div class="widget-block">
<input id="rate1" value="<?php echo $value['rating']?>" type="number" class="rating" data-max="5" data-min="0" data-size="sm" data-show-clear="false" readOnly="readOnly">
<a href="<?php echo $value['sellers_site']?>" target="#"><img class="img-responsive wow fadeInLeftBig animated" data-wow-duration="1.5s" src="<?php echo $value['$image_location']?>" alt="<?php echo $value['$author_name']?>"></a>
<br>
<a href="<?php echo $value['sellers_site']?>" class="btn btn-success" target="_blank">Buy this book</a>
</div>
</div>
<div class="col-md-6 col-md-8">
<div class="section-sub-title">
<article class="section-title-body white">
<h1 class="head-title">Author: <span><?php echo $value['$author_name']?> -</span> <?php echo $value['$title']?></h1>
<span class="point-line hidden-xs hidden-sm"></span>
<p>
<?php echo $value['$review']?>
</p>
</article>
</div>
</div>
</div>
</div>
<?php } ?>
谢谢！
答案 0 :(得分：3)
“＆lt;”之间有空格php中的foreach个关键字，同一行的末尾也没有左括号或冒号。尝试类似：
<?php foreach($rows as $value): ?>
....
<?php endforeach; ?>
答案 1 :(得分：1)
我也可能错误地假设通过放置我的html标签 在一个php foreach循环中，它将动态创建所有 需要的标签取决于返回的行数。
除了你犯的一些sintax错误之外，这正是它的工作原理：
1：
<? php
应该是
<?php
2：
foreach($rows as $value); ?>
应该是这个
foreach($rows as $value){ ?>
另外，如果你使用的是现代版本的PHP（5.4+），你可以使用短的php标签和短输出。
此
value="<?php echo $value['rating']?>"
等于
value="<?=$value['rating']?>"
答案 2 :(得分：0)
尝试将您的foreach更改为：
foreach($rows as $value) { ?>