Question

我的模型错误：调用未定义的方法CI_DB_mysqli_driver :: result（）

     <?php
     defined('BASEPATH') OR exit('No direct script access allowed');

     class teacher_feedback extends CI_Model {

     public function teacher_feedback_query($teacher)
      {
    $teacher_feedback_query = 'SELECT TD.name, TD.subject, TFA.answer_value,    SBI.first_name, TFSAC.comment, TFSC.comment, TFQ.teachers_feedback_question_id FROM teacher_details as TD inner join teachers_feedback_student_answer as TFSA on TFSA.teacher_id = TD.teacher_id inner join  teachers_feedback_answer as TFA on TFA.teachers_feedback_answer_id = TFSA.teachers_feedback_answer_id inner join teachers_feedback_student_answer_comment as TFSAC on TFSAC.teacher_id = TD.teacher_id inner join student_basic_info as SBI on SBI.student_id=TFSAC.student_id inner join teachers_feedback_student_comment as TFSC on TFSC.student_id = SBI.student_id inner join teachers_feedback_question as TFQ on TFQ.teachers_feedback_question_id = TFSA.teachers_feedback_question_id  where TD.teacher_id = ?';

$teacher_query = $this->db->query($teacher_feedback_query,array($teacher));
$teacher_feedback_result = $this->db->result($teacher_query);
return $teacher_feedback_result();
}
}
?>

Answer 1

尝试返回result_array（）而不仅仅是result（）

Answer 2

我认为你在这里想做的事情是错误的。应该对查询结果调用result方法，而不是db对象。

试试这个：

<?php

defined('BASEPATH') OR exit('No direct script access allowed');

class teacher_feedback extends CI_Model {

     public function teacher_feedback_query($teacher)
     {
          $teacher_feedback_query = 'SELECT TD.name, TD.subject, TFA.answer_value,    SBI.first_name, TFSAC.comment, TFSC.comment, TFQ.teachers_feedback_question_id FROM teacher_details as TD inner join teachers_feedback_student_answer as TFSA on TFSA.teacher_id = TD.teacher_id inner join  teachers_feedback_answer as TFA on TFA.teachers_feedback_answer_id = TFSA.teachers_feedback_answer_id inner join teachers_feedback_student_answer_comment as TFSAC on TFSAC.teacher_id = TD.teacher_id inner join student_basic_info as SBI on SBI.student_id=TFSAC.student_id inner join teachers_feedback_student_comment as TFSC on TFSC.student_id = SBI.student_id inner join teachers_feedback_question as TFQ on TFQ.teachers_feedback_question_id = TFSA.teachers_feedback_question_id  where TD.teacher_id = ?';

          $teacher_query = $this->db->query($teacher_feedback_query,array($teacher));
          //$teacher_feedback_result = $this->db->result($teacher_query);
          $teacher_feedback_result = $teacher_query->result();
          return $teacher_feedback_result; // Remove parenthesis, $teacher_feedback_result is not a function
     }
}

?>

修改

关于错误调用未定义的方法CI_DB_mysqli_driver :: result（）

PHP抛出此错误，因为CodeIgniter MySQLi适配器类没有方法result。这是CodeIgniter MySQLi驱动程序类。您可以检查一下，没有这样的方法result：

https://github.com/bcit-ci/CodeIgniter/blob/develop/system/database/drivers/mysqli/mysqli_driver.php

因此，当您致电$this->db->result($teacher_query)时，$this->db会附加到CI_DB_mysqli_driver，因此您会收到一个错误，即您正在调用未定义的方法。

Answer 3

在大多数情况下，由于我们在上面应用了核心php代码，而ci有其自己的应用方式，因此会出现此类错误。因此，有时我们成功地应用了一些核心代码，但有时却没有。在这种情况下，请尝试继续使用ci doc，您很可能会找到解决方案。祝你好运。

调用未定义的方法CI_DB_mysqli_driver :: result（）

3 个答案: