Question

我试图通过比较键列来将键值对附加到现有的dict列表中。

# Initial list of dict
lst = [{'NAME': 'TEST', 'TYPE': 'TEMP'},
   {'NAME': 'TEST', 'TYPE': 'PERMANENT'},
   {'NAME': 'TEST1', 'TYPE': 'TEMP'}]

# From the below list of dict, the Key (NAME only) need to compare with the initial list dict 
# and for any match need to append the rest of key value pair to the initial list of dict.
compare_lst = [{'NAME': 'TEST', 'ID': 70001, 'V_KEY': 67, 'R_KEY': 1042, 'W_ID': 22},
               {'NAME': 'TEST1','ID': 70005, 'V_KEY': 75, 'R_KEY': 1047, 'W_ID': 28}]

# Expected Out put
out = [{'NAME': 'TEST', 'TYPE': 'TEMP', 'ID': 70001, 'V_KEY': 67, 'R_KEY': 1042, 'W_ID': 22},
   {'NAME': 'TEST', 'TYPE': 'PERMANENT', 'ID': 70001, 'V_KEY': 67, 'R_KEY': 1042, 'W_ID': 22},
   {'NAME': 'TEST1', 'TYPE': 'TEMP', 'ID': 70005, 'V_KEY': 75, 'R_KEY': 1047, 'W_ID': 28}]

Answer 1

简单的方法，没有列表comps，双循环但工作正常：

out=[]

for l in lst:
    for c in compare_lst:
        if l['NAME']==c['NAME']:  # same "key": merge
            lc = dict(l)
            lc.update(c)  # lc is the union of both dictionaries
            out.append(lc)

print(out)

更多pythonic，在定义了一个帮助函数以返回2个字典的并集后：

out=[]

def dict_union(a,b):
    r = dict(a)
    r.update(b)
    return r

for l in lst:
    out.extend(dict_union(l,c) for c in compare_lst if l['NAME']==c['NAME'])

n python 3.5+，不需要union aux方法，你可以写得更简单

out = []
for l in lst:
    out.extend({**l,**c} for c in compare_lst if l['NAME']==c['NAME'])

更好：oneliner使用itertools.chain来压缩2级列表comp的结果

import itertools    
out=list(itertools.chain(dict_union(l,c) for l in lst for c in compare_lst if l['NAME']==c['NAME'] ))

for python 3.5

import itertools    
out=list(itertools.chain({**l,**c} for l in lst for c in compare_lst if l['NAME']==c['NAME'] ))

（这样做的多种方法实现了我最后几分钟所做的增量改进）

如何根据匹配的Python键，从另一个dict列表中将键值对附加到现有的dict列表中

1 个答案: