sqldf RLIKE功能

Question

我有以下mySQL查询：

sqldf( "select * from data WHERE TEXT RLIKE '[[:<:]]digital[[:>:]]' OR TEXT RLIKE '[[:<:]]data[[:>:]]' OR TEXT RLIKE '[[:<:]]agile[[:>:]]' OR (TEXT RLIKE '[[:<:]]self[[:>:]]' AND TEXT RLIKE '[[:<:]]service[[:>:]]') OR TEXT RLIKE '[[:<:]]cloud[[:>:]]' OR TEXT RLIKE '[[:<:]]insight[^[:space:]]+[[:>:]]' OR TEXT RLIKE '[[:<:]]modern[^[:space:]]+[[:>:]]'")

我想使用sqldf包在R中应用它：

data <- structure(list(Participant = 1:3, A = c("and other agile digital, things", "testing test and modern", "nothing here"), B = c("", "b", "b"), C = c("c", "c", "c")), .Names = c("Participant", "TEXT", "other", "another"), row.names = c(NA, -3L), class = "data.frame")

我想针对一些示例数据运行：

Error in sqliteSendQuery(con, statement, bind.data) : error in statement: near "RLIKE": syntax error

我收到以下错误

int getNeighborhood(const char** grid, int N, int row, int col, int& bCount, int& fCount, int& rCount, int& gCount){
   int currRow;
   int currCol;
   int countB = 0;
   int countF = 0;
   int countR = 0;
   int countG = 0;

   //loop through all 8 grids surrounding the current row and column.
   for(int i = -1; i < 2; i++)            
   {
      for(int j = -1; j < 2; j++){
         currRow = row + i;               //current row.
         currCol = col + i;               //current column.

         if(currRow >= 0 && currRow < N && currCol >= 0 && currCol < N){
            if(grid[row][col] == 'B')
            {
               ++countB;
            }
            if(grid[row][col] == 'F')
            {
               ++countF;
            }
            if(grid[row][col] == 'R')
            {
               ++countR;
            }
            if(grid[row][col] == 'G')
            {
               ++countG;
            }
         }
      }
   //return statement required
   }

看起来这个包不喜欢RLIKE语句。为什么，以及如何解决这个问题？

Answer 1

包含所需结果总是好的。基于this source，您似乎想要提取TEXT - 列foo后面跟有非空格字符的行。

你也可以在R grep - 函数：

中完成这项工作

dat[grep('.*(foo)[^ ]', dat$TEXT),]

给出：

  Participant                  TEXT other another
1           1 and other foo, things             c

_{PS：最好不要为数据集指定与函数相同的名称;出于这个原因，我使用了dat而不是data}