Question

我是一名新编码员，我正在尝试为学校项目创建假日预订网站。

我正在使用Jquery UI日期选择器，我正在尝试使用日期范围从我的mysql预订表中提取不可用的日期。

我的表格为bookings

我的日期字段为datein和dateout

示例：

Row 1

2016-12-15 to 2016-12-18

Row 2

2017-01-15 to 2017-01-18

Next Row Etc...

Desired Output

2016-12-15

2016-12-16

2016-12-17

2016-12-18

2017-01-15

2017-01-16

2017-01-17

2017-01-18

然后使用PHP将它们回显到像这样的json数组中：

["2016-12-15", "2016-12-16", "2016-12-17", "2016-12-18", "2017-01-15", "2017-01-16", "2017-01-17", "2017-01-18"]

如果我的问题不明确但我只是在学习，那么感谢任何可能有所贡献的人道歉。

Answer 1

我认为（除了数组部分）这里是MYSQL查询。

mysql_select_db($database, $connection);
$query_rsunavaildates = "select selected_date from 
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
 (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v,
bookings
where selected_date between datein and dateout
ORDER BY selected_date ASC";
$rsunavaildates = mysql_query($query_rsunavaildates, $connection) or die(mysql_error());
$row_rsunavaildates = mysql_fetch_assoc($rsunavaildates);
$totalRows_rsunavaildates = mysql_num_rows($rsunavaildates);

如果任何人可以帮助json数组我会很感激。我可以使数组回显，但格式不正确。我需要输出[＆＃34; 2015-01-02＆＃34;，＆＃34; 2015-01-03＆＃34;，＆＃34; etc＆＃34;]

从Mysql中的日期范围中提取所有日期

1 个答案: