所以我使用fscanf
来读取文件,我正在尝试将这些字符串放入数组中。它似乎工作,但我只是将最后一个字符串放入我的数组。当我尝试打印它时,我只打印我最后一个字符串的字符。我没有包含我的方法,因为它不会影响fscanf
所做的事情,以防任何人感到困惑。此外,我的CMDLINE文件具有以下字符串foo barr tar 526-4567 456-8792
。
输出是:
456-8792
56-8792
6-8792
等...
2
以下是代码:
int main (int argC, char *argV[]) {
FILE *fp;
int index;
int ret;
char str[1000];
//Need at least 2 files to begin program
if (argC < 3) {
fprintf(stderr, "Usage: %s file\n", argV[0]);
exit(1);
}//if statemtn
//check to see if the CMDLINE file is in the arguements
ret = scanC(argC, argV);
//if no CMDLINE file is found, print error and exit
if (ret == 1) {
fprintf(stderr, "you must provide a CMDLINE file\n");
exit(1);
}
//iterate and open CMDLINE file and read from it
for (index = 0; index < argC; index++) {
if (strcmp(argV[index], "CMDLINE") == 0) {
fp = fopen(argV[index], "r");
//error check
if (fp == NULL) {
fprintf(stderr, "Counld not open file %s\n", argV[index]);
exit(1);
}//if statment
//read from fscanf and put it's arguements into an array
while (!feof(fp)) {
char *p2 = str;
//scan the strings of the file into str array
while (fscanf(fp, "%s", p2) != EOF) {
p2++;
}//while loop 2
}//while lop 1
//close the file for it is not needed to be open anymore
fclose(fp);
}//if statement
}//for looop
char *p;
p = str;
int j;
for (j = 0; j < strlen(str); j++) {
printf("%s\n", p);
p++;
}
return 1;
}
答案 0 :(得分:2)
char *p;
p = str;
int j;
for (j = 0; j < strlen(str); j++)
{
printf("%s\n", p);
p++;
}
您有一个字符串,例如"abcd"
,您可以将其打印为printf("%s\n", str);
而不是从不同的偏移量开始打印相同的字符串。结果如下:
abcd
bcd
cd
d
也许你对“字符数组”和“数组字符串”
感到困惑//This will reserve 100 character arrays, or 100 strings
char *arr[100];
int count = 0;
while (fscanf(fp, "%999s", str) == 1)
{
arr[count] = malloc(strlen(str) + 1);
strcpy(arr[count], str);
count++;
if (count == 100)
break;
}
int i;
for (i = 0; i < count; i++)
printf("%s\n", arr[i]);
在实际应用程序中,您使用malloc
和realloc
来分配足够大的字符串数组来读取文件。
答案 1 :(得分:1)
您可以使用标记设置“当前字符”:
char *p2 = str;
size_t k = 0;
size_t pos = 0;
//scan the strings of the file into str array at position pos
while((k = fscanf(fp, "%s", p2 + pos)) != EOF){
// update pos
pos += k;
p2++;
}//while loop 2
这将使整个文件存储在您的字符串中 提供它不到1000个字符! 否则只需在while循环中添加一个安全措施。