Question

我一直在尝试使用几种静态方法制作这种打勾脚趾游戏。我仍然相对较新，并不能完全弄清楚鼠标点击的整个想法。我已经阅读过关于mouseclick和mouseevent的内容，但它没有完全合理，我尝试时会遇到很多错误。最初我有自己的方法中的鼠标信息部分，但后来我无法弄清楚如何返回x和y值。所以我添加方法来填充下面的数组。现在我搞砸了它并管理他们自己的方法，但仍然有运行程序的问题。（他们不必使用他们自己的方法，我只是认为它会简化事情）当我运行这个程序时，它所做的就是打印无限量的行，说明我点击的行和列并放入O无论是否点击，第一行和第一列都是。此外，它似乎也不会在玩家之间切换。如果有人能帮助我，我将非常感激。谢谢！

import java.util.*;
public class Game {

  public static int x;
  public static int y;
  public static double a;
  public static double b;
  public static int empty = 0;
  public static int Cross = 1;
  public static int Oh = -1;
  public static double[][] board = new double[3][3];
  public static int currentPlayer;
  public static int Point;


  public static void main (String args[]) {



    drawBoard();


    Fill();
  }

    public static void drawBoard(){
    StdDraw.setXscale(0,9);
    StdDraw.setYscale(0,9);
    StdDraw.setPenRadius(.01);
    StdDraw.setPenColor(StdDraw.BLACK);
    StdDraw.line(0,3,9,3);
    StdDraw.line(0,6,9,6);
    StdDraw.line(3,0,3,9);
    StdDraw.line(6,0,6,9);
  } //end draw board




  //get mouse click and turn into array spot
  public static void Mouse(){
    while(true){
      if (StdDraw.mousePressed()){
        a = StdDraw.mouseX();
        b = StdDraw.mouseY();
        System.out.println( a + " " + b);
      }



      //set column
      if ( 0<=a && a< 3){
        x =  0;}
      if ( 3<=a && a<6){
        x = 1;}
      if ( 6<=a && a< 9){
        x = 2;}
      //set row
      if ( 0<=b && b< 3){
        y = 0;}
      if ( 3<=b && b< 6){
        y = (int)1;}
      if ( 6<=b && b< 9){
        y = 2;}
      System.out.println("You clicked in Row" + x + "and column" +y);
    }
  }

      public static void Fill(){
      //fill array
        Mouse();
      boolean validInput = false;
      do{    
      for (int i = 0 ; i <=9 ; i++){
    if (i % 2 == 0){
          currentPlayer = Cross;
        }
        else {
          currentPlayer = Oh;
        }}
          if (0 <= x && x<=2 && 0 <=y && y <= 2 && board[x][y] == 0){

            //fill array spot
        board[x][y] = currentPlayer;
        //check game status and print board
        GameStatus();
        PrintBoard();
        validInput = true; //input is good, exit the loop
        }
        else { 
          System.out.println("This move is not valid. Try again.");
          }
      }while (!validInput);
    }














    public static void PrintBoard(){
  for (int j = 0; j<=2; j++){
    for (int k = 0; k<=2; k++){
      if (board[j][k] == 0){
        //do nothing leave empty
      }
      if (board[j][k] == 1){
        double l = ((j+1) * 3) - 1.5;
        double m = ((k+1) * 3) - 1.5;
        //print x
        StdDraw.text(l,m,"X");}
      if (board[j][k] == -1){
        double l = ((j+1) * 3) - 1.5;
        double m = ((k+1) * 3) - 1.5;
        //print O
        StdDraw.text(l,m,"O");}
    }
  }
    }


  public static void GameStatus(){
        //check for win
        if (// First column
            board[0][0] == currentPlayer
              && board[0][1] == currentPlayer
              && board[0][2] == currentPlayer
              //second column
              || board[1][0] == currentPlayer
              && board[1][1] == currentPlayer
              && board[1][2] == currentPlayer
              //third column
              || board[2][0] == currentPlayer
              && board[2][1] == currentPlayer
              && board[2][2] == currentPlayer
              //first row
              ||board[0][0] == currentPlayer
              && board[1][0] == currentPlayer
              && board[2][0] == currentPlayer
              //second row
              || board[0][1] == currentPlayer
              && board[1][1] == currentPlayer
              && board[2][1] == currentPlayer
              //third row
              || board[0][2] == currentPlayer
              && board[1][2] == currentPlayer
              && board[2][2] == currentPlayer
              //diagonal 1
              || board[0][2] == currentPlayer
              && board[1][1] == currentPlayer
              && board[2][0] == currentPlayer
              // diagonal 2
              || board[2][2] == currentPlayer
              && board[1][1] == currentPlayer
              && board[0][0] == currentPlayer){
          //X win
          while (currentPlayer==1){
            StdDraw.text(0.5, 0.5, "X Won!");}
          //O win
          while (currentPlayer==-1){
            StdDraw.text(0.5, 0.5, "O Won!");}
          return;
        }

        //draw
        if  (board[0][0] != 0 
               && board[0][1] != 0
               && board[0][2] != 0
               && board[1][0] != 0
               && board[1][1] != 0
               && board[1][2] != 0
               && board[2][0] != 0
               && board[2][1] != 0
               && board[2][2] != 0){
          StdDraw.text(0.5, 0.5, "Cat's Game!");
          return;}

        //still playing
        else {
          System.out.println("Keep Playing.");
          //keep playing
        }

  }//Ends playerMove

}// end game

Answer 1

首先，你有一个“while（true）”语句。这是一个无限循环，你需要一些东西告诉它爆发。这就是你看到垃圾文本的原因。

其次，您用于获取“mousePressed”事件的StdDraw对象在哪里？如果您只是点击一下，我建议使用“MOUSE_CLICKED”事件，但即使您使用mousePressed，也需要确保在没有按下鼠标时它没有检测到它。

Answer 2

它继续打印行，因为你在Mouse（）方法中创建了一个无限循环，并且每秒数百万次检查if语句中的条件。

我建议创建一个单独的方法，例如gameLoop（），并在gameLoop（）中调用所有其他方法[精心构造]。

在stdlib包文档中我们读到：

[键盘和鼠标输入]您应该在动画循环中使用这些方法，等待一小段时间再尝试轮询鼠标的当前状态。

所以在你的游戏中你可以尝试这样的事情：

gameLoop() {
    isPlaying = true;
    drawBoard();
    ...;
    while (isPlaying) {
        isPressed = false;
        checkMousePressed();
        if (isPressed) {
            checkMove();
            ...;
        }  
        Thread.sleep(100); // 100 ms, so you repeat the loop 10 times/sec.
    }
    printWinner();
}

此外，方法名称的一个好习惯是使用动词，而不是名词。因此，你说的是做什么，换句话说，你说出目的，因此更容易遵循程序的逻辑。如果你称之为mouse（），那么该方法应该做什么就不清楚了。

Java鼠标单击问题

2 个答案: