Question

我遇到了问题，我试图调试它，但我找不到任何东西

#include <stdio.h>
#include <stdlib.h>

struct Process {
    int id;
    int at;
    int bt;
    int rt;
    struct Process *next;
} *tmp;

struct Queue {
    struct Process *head, *tail;
};

struct Process *pop(struct Queue *queue) {
    if (queue->head == NULL) {
        return NULL;
    }
    tmp = queue->head;
    queue->head = queue->head->next;
    return tmp;
}

int main() {
    struct Queue queues[3];
    struct Process *working;
    for (int i = 0; i < 3; i++) {
        queues[i].head = NULL;
    }
    FILE *processesFile = fopen("processes.txt", "r");
    while (!feof(processesFile)) {
        fscanf(processesFile, "%d %d %d", &id, &at, &bt);
        push(&queues[0], id, at, bt);
    }
    working = pop(&queues[0]); // HERE IS THE PROBLEM, It is removing the first element but causing segmentation error
    return 0;
}

我删除了推送部分，我可以成功地推送5个值并打印整个队列而没有任何问题

Answer 1

我没有看到push（＆amp; queues [0]，id，at，bt）;的定义。 fscanf（processesFile，“％d％d％d”，＆amp; id，＆amp; at，＆amp; bt）;这里使用变量id，at和bt但它们实际上并不作为结构变量访问。

从队列中弹出时C中的分段错误

1 个答案: