正则表达式 - 排除搜索结果

Question

我正在寻找日志文件中的更改。 这是一个例子：

"2-11-2016 11:39:27 CET","vladyslav.kushney@gmail.com","Changed Class1 Apex Class code","Apex Class",""
"2-11-2016 12:39:27 CET","vladyslav.kushney@gmail.com","Changed Class2 Apex Class code","Apex Class",""
"2-11-2016 13:39:27 CET","vladyslav.kushney@gmail.com","Changed Class2 Apex Class code","Apex Class",""
"2-11-2016 14:39:27 CET","vladyslav.kushney@gmail.com","Changed Class1 Apex Class code","Apex Class",""
"2-11-2016 15:39:27 CET","vladyslav.kushney@gmail.com","Changed Class3 Apex Class code","Apex Class",""
...
"2-11-2016 15:39:27 CET","vladyslav.kushney@gmail.com","Changed FirstClass Apex Class code","Apex Class",""
"2-11-2016 15:39:27 CET","vladyslav.kushney@gmail.com","Changed SecondClass Apex Class code","Apex Class",""

我已经知道我改变了Class1和Class2。所以我需要找到我改变的另一个类（本例中为SecondClass）

如何创建正则表达式以排除Class1和Class2？ 我在Sublime Text中使用搜索

我已经尝试过： Regular expression to match a line that doesn't contain a word? 结果：

RegEx to exclude a specific string constant 结果：

Answer 1

您似乎需要将一些未跟随数字的字符串（您将在每次匹配后手动添加）匹配为整个单词。

您可以使用带有替代组(...|...|etc.)和字边界\b的基于正面的负面前瞻：

"vladyslav.kushney@gmail.com","Changed Class(?!(123|12|1|2|3)\b)
|
---------- a known part --------------------|negative lookahead|

如果已知部分跟随123或12等，后跟字边界（请参阅(123|12|1|2|3)\b），则否定前瞻会使匹配失败。捕获组可以用仅用于分组的非捕获组替换：(123|12|1|2|3) =＆gt; (?:123|12|1|2|3)（意味着它不会将任何子文本放入$1，第1组）。