Question

我有一个包含内容的文本文件：

A;B;C;D
a;b;c;d

我正在读取python中的文件，并希望重新排列列，例如 -

B;C;D;A
b;c;d;a

我试过阅读专栏 -

file = open('add.txt','r')
text = file.read()
column1 = x[0] for x in text

但这并没有帮助。所以我需要一种方法来转换它。

Answer 1

您可以使用csv模块将文件读入列表，然后只需重新编制列表顺序索引。

import csv
list_variable = []
with open("file.txt") as add_txt:
    reader = csv.reader(add_txt, delimiter =';')
    for line in reader:
        line += [line.pop(0)]
        list_variable.append(line)

Answer 2

您可以使用元组/可迭代解包来执行此操作

# Create a palette of 4 colors of hues from 0 to 360, saturations between
# 0.1 and 0.5, and lightness from 0.6 to 0.85
pal <- qualpal(n = 4, list(h = c(0, 360), s = c(0.1, 0.5), l = c(0.6, 0.85)))

# Look at the colors in hex format
pal$hex
#> [1] "#6F75CE" "#CC6B76" "#CAC16A" "#76D0D0"

# Create a palette using one of the predefined color subspaces
pal2 <- qualpal(n = 4, colorspace = "pretty")

# Distance matrix of the DIN99d color differences
pal2$de_DIN99d
#>        #69A3CC #6ECC6E #CA6BC4
#> 6ECC6E      22                
#> CA6BC4      21      30        
#> CD976B      24      21      21

plot(pal2)

Answer 3

您不需要使用csv模块作为建议的答案：

with open('add.txt', 'r') as file:
    text = file.read()
    result = []
    for line in text.splitlines():
        cols = line.split(';')
        cols = cols[1:] + [cols[0]]
        result.append(cols)

print(result)

输出：

[['B', 'C', 'D', 'A'], ['b', 'c', 'd', 'a']]

从文件中读取文本并重新排列列？

3 个答案: