我在项目中安装了Alamofire,现在就是我所做的。
我安装了postman并将我的网址和内部的xml对象放在一起,我得到了我的结果。
这是我用邮递员完成的事情的图片
我现在如何使用Alamofire或SWXMLHash发送邮件时发送邮件
提前致谢!
修改
我从另一个问题尝试了这个:
Alamofire.request(.POST, "https://something.com" , parameters: Dictionary(), encoding: .Custom({
(convertible, params) in
let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest
let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
mutableRequest.HTTPBody = data
return (mutableRequest, nil)
}))
.responseJSON { response in
print(response.response)
print(response.result)
}
}
但它没有发送任何东西
这是日志:
可选({URL: https://something.com} {状态代码:200,headers { 连接="保持活力&#34 ;; " Content-Length的" = 349; "内容类型" =" application / xml&#34 ;; Date =" Wed,02 Nov 2016 21:13:32 GMT&#34 ;; Server = nginx; "严格,运输和安全" =" max-age = 31536000; includeSubDomains&#34 ;; }})
FAILURE
编辑
如果您没有简单的添加,请不要忘记通过参数,参数:Dictionary()
答案 0 :(得分:6)
使用Swift 3和Alamofire 4
let stringParams : String = "<msg id=\"123123\" reqTime=\"123123\">" +
"<params class=\"API\">" +
"<param name=\"param1\">123213</param>" +
"<param name=\"param2\">1232131</param>" +
"</params>" +
"</msg>"
let url = URL(string:"<#URL#>")
var xmlRequest = URLRequest(url: url!)
xmlRequest.httpBody = stringParams.data(using: String.Encoding.utf8, allowLossyConversion: true)
xmlRequest.httpMethod = "POST"
xmlRequest.addValue("application/xml", forHTTPHeaderField: "Content-Type")
Alamofire.request(xmlRequest)
.responseData { (response) in
let stringResponse: String = String(data: response.data!, encoding: String.Encoding.utf8) as String!
debugPrint(stringResponse)
}
答案 1 :(得分:3)
使用Swift 3和Alamofire 4,您可以创建自定义ParameterEncoding
。与任何其他XML编码主体一样,SOAP消息可以使用此参数编码,如以下示例所示。可以类似地创建其他XML正文编码(检查它所在的行urlRequest.httpBody = ...
):
struct SOAPEncoding: ParameterEncoding {
let service: String
let action: String
func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
var urlRequest = try urlRequest.asURLRequest()
guard let parameters = parameters else { return urlRequest }
if urlRequest.value(forHTTPHeaderField: "Content-Type") == nil {
urlRequest.setValue("text/xml", forHTTPHeaderField: "Content-Type")
}
if urlRequest.value(forHTTPHeaderField: "SOAPACTION") == nil {
urlRequest.setValue("\(service)#\(action)", forHTTPHeaderField: "SOAPACTION")
}
let soapArguments = parameters.map({key, value in "<\(key)>\(value)</\(key)>"}).joined(separator: "")
let soapMessage =
"<s:Envelope xmlns:s='http://schemas.xmlsoap.org/soap/envelope/' s:encodingStyle='http://schemas.xmlsoap.org/soap/encoding/'>" +
"<s:Body>" +
"<u:\(action) xmlns:u='\(service)'>" +
soapArguments +
"</u:\(action)>" +
"</s:Body>" +
"</s:Envelope>"
urlRequest.httpBody = soapMessage.data(using: String.Encoding.utf8)
return urlRequest
}
}
然后像这样使用它:
Alamofire.request(url, method: .post, parameters: ["parameter" : "value"], encoding: SOAPEncoding(service: "service", action: "action"))
答案 2 :(得分:2)
假设您在请求中缺少有效的HTTP标头,更新的请求可能如下所示:
Alamofire.request(.POST, "https://something.com", parameters: Dictionary() , encoding: .Custom({
(convertible, params) in
let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest
let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
mutableRequest.HTTPBody = data
mutableRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
return (mutableRequest, nil)
}))
.responseJSON { response in
print(response.response)
print(response.result)
}
}
所以,基本上你应该添加一行
mutableRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
<强>更新强>:
尽量相同,但请使用responseData
或responseString
代替responseJSON
,因为您的回复可能不是JSON