我需要走js对象并将所有点替换为此对象键中的下划线 例如
{a.a:"test"}
to
{a_a:"test"}
这是我的代码。
Object.getOwnPropertyNames(match).forEach(function(val, idx, array) {
if(val.indexOf(".") != -1){
val.replace(/\./g,'_');
}
});
谢谢,但我的对象问题不那么简单, 像这样
{
"a.a":{
"nee.cc":"sdkfhkj"
},
"b.b": "anotherProp"
}
答案 0 :(得分:2)
使用Array.prototype.reduce()
创建一个新对象,并使用简单的字符串替换替换道具名称中的点,而不使用正则表达式:
function transformKeys(obj) {
return Object.keys(obj).reduce(function(o, prop) {
var value = obj[prop];
var newProp = prop.replace('.', '_');
o[newProp] = value;
return o;
}, {});
}
var result = transformKeys({"a.a":"test", "b.b": "anotherProp"});
console.log(result);
答案 1 :(得分:2)
使用lodash,这是一个函数,它将递归地替换每个对象键的下划线点。
并添加了一项测试以验证结果。
function replaceDotWithUnderscore(obj) {
_.forOwn(obj, (value, key) => {
// if key has a period, replace all occurences with an underscore
if (_.includes(key, '.')) {
const cleanKey = _.replace(key, /\./g, '_');
obj[cleanKey] = value;
delete obj[key];
}
// continue recursively looping through if we have an object or array
if (_.isObject(value)) {
return replaceDotWithUnderscore(value);
}
});
return obj;
}
// --------------------------------------------------
// Run the function with a test to verify results
// -------------------------------------------------
var input = {
"a.a": {
"nee.cc": "sdkfhkj"
},
"b.b": "anotherProp"
};
var result = replaceDotWithUnderscore(input);
// run a quick test to make sure our result matches the expected results...
var expectedResult = {
"a_a": {
"nee_cc": "sdkfhkj"
},
"b_b": "anotherProp"
};
console.log(result);
console.assert(_.isEqual(result, expectedResult), 'result should match expected result.');

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
&#13;
答案 2 :(得分:0)
以下代码可能有助于您解决问题。
Object.keys(yourObj).forEach(function(v){
yourObj[v.replace(".", "_")] = yourObj[v];
delete yourObj[v];
console.log(yourObj);
});
答案 3 :(得分:0)
您可以使用键为“_”而不是“。”的属性填充新对象。 :
var transformKeys = obj => {
result = {};
Object.keys(obj).forEach(x => {
var y = x.replace(".", "_");
result[y] = obj[x];
});
return result;
}
console.log(transformKeys({"a.a":"test", "b.b": "anotherProp"}));
// { a_a: 'test', b_b: 'anotherProp' }
答案 4 :(得分:0)
创建一个循环对象的函数并检查对象,然后重用函数。
var obj = {
"a.a":{
"nee.cc":"sdkfhkj"
},
"b.b": "anotherProp"
};
d_u(obj); // change dot to underscore function
function d_u(obj){
for(var i in obj) {
if (typeof obj[i] == "object") d_u(obj[i]);
obj[i.replace(/\./g,'_')] = obj[i];
delete obj[i]; // delete old object [current]
}
}
console.log(obj);