我有角度前端的JSON响应。回应是:
var results = (from t in CurrentDataSource.Table1
where t.Manager == userId && t.Profile != null
select t.Profile.GetValueOrDefault()).ToList();
我想在laravel中获取所有卡片名称。在laravel控制器功能中我的代码如下:它返回一些错误。我不知道如何获取所有这些var element = $('.banner').find('h1'); // or other container...
if (element.length) $('h1').not(element).remove();
。
{
"selected": null,
"lists": [
{
"board one": [
{
"card_name": "Card 10",
"id": 1,
"card_unique_id": "PC1"
},
{
"card_name": "card 11",
"id": 2,
"card_unique_id": "PC2"
},
{
"card_name": "card12",
"id": 3,
"card_unique_id": "PC3"
},
{
"card_name": "adfaf",
"id": 12,
"card_unique_id": "PC12"
},
{
"card_name": "fa df af ad",
"id": 13,
"card_unique_id": "PC13"
}
],
"BoardId": "PB1"
},
{
"board two": [
{
"card_name": "Card 20",
"id": 4,
"card_unique_id": "PC4"
},
{
"card_name": "CArd 21",
"id": 5,
"card_unique_id": "PC5"
},
{
"card_name": "card 23",
"id": 6,
"card_unique_id": "PC6"
},
{
"card_name": "Card 24",
"id": 7,
"card_unique_id": "PC7"
}
],
"BoardId": "PB2"
},
{
"board three": [
{
"card_name": "Card 30",
"id": 8,
"card_unique_id": "PC8"
},
{
"card_name": "card 31",
"id": 9,
"card_unique_id": "PC9"
},
{
"card_name": "card 32",
"id": 10,
"card_unique_id": "PC10"
}
],
"BoardId": "PB3"
},
{
"new board": [
{
"card_name": "card 40",
"id": 11,
"card_unique_id": "PC11"
}
],
"BoardId": "PB4"
}
]
}
请任何人帮忙。 谢谢高级..
答案 0 :(得分:3)
将true
添加到json_decode()
以获取关联数组:
$get_result_arr = json_decode($response->getContent(), true);
然后遍历此数组并获取每个card_name
:
foreach ($get_result_arr['lists'] as $list) {
foreach (array_values($list)[0] as $card) {
echo $card['card_name'];
}
}