Question

到目前为止，我只能在整个字符串的末尾删除不需要的字符。但我不知道如何在每个单词的结尾处获得相同的结果，而不是在每个单词的开头删除它。

Here就是我所拥有的。

function removeCharacter(str){
  return str.replace(/[!]*$/g, '');
}

console.log(removeCharacter('Hello, my name is Ivan Ivanych.!'));
console.log(removeCharacter("!!Hello there.!!"));
console.log(removeCharacter("Hello,!!! I!! am! Ivan."));
console.log(removeCharacter("!!!Hello,!!! !!I!! !am! Ivan."));

Answer 1

这将做你想要的：

＆＃13;

function removeCharacter(str){
  return str.replace(/([a-z,.])!+/gi, '$1');
}

console.log(removeCharacter('Hello, my name is Ivan Ivanych.!'));
console.log(removeCharacter("!!Hello there.!!"));
console.log(removeCharacter("Hello,!!! I!! am! Ivan."));
console.log(removeCharacter("!!!Hello,!!! !!I!! !am! Ivan."));

＆＃13;

Answer 2

试一试。它只会删除一个单词末尾的感叹号。

function removeCharacter(str){
  return str.replace(/(!+)(?=\s|$)/g, '');
}

console.log(removeCharacter('Hello, my name is Ivan Ivanych.!'));
console.log(removeCharacter("!!Hello there.!!"));
console.log(removeCharacter("Hello,!!! I!! am! Ivan."));
console.log(removeCharacter("!!!Hello,!!! !!I!! !am! Ivan."));

使用正则表达式删除每个单词末尾的特定字符

2 个答案: