Question

当用户输入0时，程序应该停止。我无法弄清楚如何做到这一点。例如：输入1到100之间的整数：2 5 6 5 4 3 23 43 2 0 2发生2次 3发生1次 4发生1次 5次发生2次 6次发生1次 23次发生1次 43次出现

我的代码打印0。

public class CountOccurrences {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);

System.out.println("Enter ten integers between 1 and 100: ");
String userInput = input.nextLine(); 

//this splits the user input into an array using a space
String[] inputString = userInput.split(" "); 
String[] previousValues = new String[inputString.length];

int count = 1;  

//Compare elements and update count for new string
  for (int i = 0; i < inputString.length; i++) {
   for (int j = i+ 1; j < inputString.length; j++) {
     if (inputString[i].equals(inputString[j]) && notFound (previousValues, inputString[i]) {                                  `               
      count++;   
    } 
 }

  //Prints only unique strings
  if(!userInput.equals("0")){
    if (notFound(previousValues,inputString[i])) {
      if (count>1) {
        System.out.println(inputString[i] + " occurs " + count + " times");
      } else { 
        System.out.println(inputString[i] + " occurs " + count + " time");
      }
          count = 1;
      }
      if (notFound(previousValues,inputString[i])) {
        previousValues[i] =   inputString[i];
      }
}}


}

//This method returns a boolean value. It is true if the string is not in the array  and vice versa

public static boolean notFound(String[] pastValues, String currentString) {
boolean valueNotFound = true;
int index = 0;
while(index < pastValues.length && valueNotFound) {
  if ((pastValues!= null) &&(currentString.equals(pastValues[index]))) {
    valueNotFound = false;
  }
  index++;
  }
  return valueNotFound;
  }

//Method for printing an array
  public static void printArray(String [] a) {
    for (int i = 0; i < a.length; i++) {
      System.out.print(a[i]+ "  ");

   }

   }

 }

Answer 1

您可以通过添加else条件并使用System.exit(0)来告诉用户程序将要终止。

static void exit（int status）终止当前正在运行的程序或Java虚拟机。

状态0表示程序执行完成，没有异常。

您可以查看API here

如何在代码中添加标记值？

1 个答案: