Xceed datagrid显示组合框

Question

我想使用“Xceed DataGrid for WPF”社区版来显示WPF应用程序中已经正确用于Propertygrid的项目。

文本框（名字）工作正常，但组合框不起作用。问题是组合框没有填充任何东西而且它没有正确设置性别。我的简单代码如下所示。

XAML：

    <Window.Resources>
            <xcdg:DataGridCollectionViewSource x:Key="mySource" Source="{Binding Path=SelectedEntity}" />
</Window.Resources>
<Grid>
    <xcdg:DataGridControl ItemsSource="{Binding Source={StaticResource mySource}}" AutoCreateColumns="True">
        <xcdg:DataGridControl.Columns>
            <xcdg:Column FieldName="FirstName" Title="First Name" />
            <xcdg:Column  FieldName="Gender" Title="Gender" >
                <xcdg:Column.CellContentTemplate>
                    <DataTemplate x:Name="clmGenderTmp">
                        <ComboBox SelectedValuePath="GenderID"
                            DisplayMemberPath="Name"
                            ItemsSource="{Binding Path=SelectedEntity.Gender, RelativeSource={RelativeSource AncestorType={x:Type Window}}}"
                            SelectedValue="{xcdg:CellEditorBinding}"/>
                    </DataTemplate>
                </xcdg:Column.CellContentTemplate>
            </xcdg:Column>
        </xcdg:DataGridControl.Columns>
    </xcdg:DataGridControl>
</Grid>

Xaml.cs是：

InitializeComponent();
this.DataContext = new MainWindowViewModel();

数据类是：

using System.ComponentModel;
using Xceed.Wpf.DataGrid;  
public enum Genders { Male, Female  }
public class Person
{
    public Person(string firstName, Genders gender)
    {
        FirstName = firstName;
        Gender = gender;
    }

    [DisplayName("Given name")]
    public string FirstName { get; set; }

    [Browsable(true)]
    public Genders Gender {  get;  set; }
}

查看模型是：

public class MainWindowViewModel
{
    public List<object> SelectedEntity { get; set; }
    public MainWindowViewModel()
    {
        SelectedEntity = new List<object>();                    
        this.SelectedEntity.Add(new Person("Mathew", Genders.Male));
        this.SelectedEntity.Add(new Person("Mark", Genders.Female));
    }
}

Answer 1

似乎Window没有属性SelectedEntity。 ;-)你想要绑定的是DataContext.SelectedEntity.Gender。无论如何，这根本不起作用，因为你试图将单个值（Gender）绑定为ItemsSource。

您需要为组合框提供（枚举）值列表。 How to bind an enum to a combobox control in WPF?

修改

由于我的答案显然不够具体，我提供了一个完整的例子：

XAML：

<ItemsControl ItemsSource="{Binding}">
    <ItemsControl.ItemTemplate>
        <DataTemplate>
            <Grid>
                <Grid.ColumnDefinitions>
                    <ColumnDefinition />
                    <ColumnDefinition />
                </Grid.ColumnDefinitions>
                <TextBlock Text="{Binding Firstname}"
                            Margin="10" />
                <ComboBox ItemsSource="{Binding Path=AvailableGenders}"
                            SelectedValue="{Binding Path=Gender}"
                            Grid.Column="1" />
            </Grid>
        </DataTemplate>
    </ItemsControl.ItemTemplate>
</ItemsControl>

PersonViewModel：

public class PersonViewModel : ViewModelBase
{
    private Genders _gender;
    private string _firstname;
    public string Firstname
    {
        get
        {
            return _firstname;
        }
        set
        {
            _firstname = value;
            OnPropertyChanged();
        }
    }

    public Genders Gender
    {
        get
        {
            return _gender;
        }
        set
        {
            _gender = value;
            OnPropertyChanged();
        }
    }

    public List<Genders> AvailableGenders

    {
        get
        {
            return Enum.GetValues(typeof(Genders)).Cast<Genders>().ToList();
        }
    }

}

MainWindow Ctor：

public MainWindow()
    {
    InitializeComponent();

    List<PersonViewModel> persons = new List<PersonViewModel>();


    persons.Add(new PersonViewModel() { Firstname = "John", Gender = Genders.female });
    persons.Add(new PersonViewModel() { Firstname = "Partyboy", Gender = Genders.male });
    persons.Add(new PersonViewModel() { Firstname = "r2d2", Gender = Genders.robot });
    persons.Add(new PersonViewModel() { Firstname = "KlausMaria", Gender = Genders.shemale });

    DataContext = persons;


}

Answer 2

我从How to add ComboBox column in XCeed DataGridControl (WPF)

得到了一个类似的例子

如果有人遇到同样的问题，只需发布​​我的代码。

ViewModel：

public class ViewModel
{
    public DataTable Persons { get; set; }
    public DataTable Gender { get; set; }
    public ViewModel()
    {
        Persons = new DataTable();
        Persons.Columns.Add("FirstName", typeof(string));
        Persons.Columns.Add("GenderID", typeof(int));

        Persons.Rows.Add("Mathew",1);
        Persons.Rows.Add("Gil", 2);

        Gender = new DataTable();
        Gender.Columns.Add("Name", typeof(string));
        Gender.Columns.Add("GenderID", typeof(int));

        Gender.Rows.Add("Male", 1);
        Gender.Rows.Add("Female", 2);
    }
}

代码背后：

InitializeComponent();
viewModel = new ViewModel();
this.DataContext = viewModel;

<强> XMAL：

<Grid>
    <Grid.Resources>
        <Style TargetType="{x:Type xcdg:GroupByControl}">
            <Setter Property="Visibility" Value="Collapsed"/>
        </Style>
    </Grid.Resources>

    <xcdg:DataGridControl ItemsSource="{Binding Persons}" > 
        <xcdg:DataGridControl.Columns>
            <xcdg:Column x:Name="clmFN" FieldName="FirstName"/>
            <xcdg:Column x:Name="clmGender" FieldName="GenderID">
                <xcdg:Column.CellContentTemplate>
                    <DataTemplate x:Name="clmGenderTmp">
                        <ComboBox SelectedValuePath="GenderID"
                            DisplayMemberPath="Name"
                            ItemsSource="{Binding Path=DataContext.Gender, RelativeSource={RelativeSource AncestorType={x:Type Window}}}"
                            SelectedValue="{xcdg:CellEditorBinding}"/>
                    </DataTemplate>
                </xcdg:Column.CellContentTemplate>
            </xcdg:Column>
        </xcdg:DataGridControl.Columns>
    </xcdg:DataGridControl>
</Grid>