Question

我正在尝试使用javascript创建一个非常简单的基于文本的冒险游戏。我很新，我觉得使用一些函数，变量和if-else语句会很棒。我写了一些代码来提示屏幕询问年龄，并给出结果。

confirm("Ready to play?");
var age = prompt("How old are you?");
if (age >= 18) {
    document.write(" "); 
} else {
    document.write("You're less than 18? You better just stay home.");
}

document.write("<button> Sounds like you're ready.</button>");

var gender = prompt("Male","Female");
if(gender = "Male") {
    document.write("Sounds good!");
} else if(gender = "Female") {
    document.write("Sounds good!");
} else if {
    document.write("You're a damn liar");
    };
};

如果我只运行代码的上半部分，一切都会正常运行。但是，如果我尝试运行性别提示，与原始代码一起运行，它将无法运行。有什么建议？

Answer 1

此代码应该有效：

confirm("Ready to play?");
var age = prompt("How old are you?");
if (age >= 18) {
    document.write(" "); 
} else {
    document.write("You're less than 18? You better just stay home.");
}

document.write("<button> Sounds like you're ready.</button>");

var gender = prompt("Are you Male or Female?");
if(gender == "Male") {
    document.write("Sounds good!");
} else if(gender == "Female") {
    document.write("Sounds good!");
} else {
    document.write("You lie...");
}

基本上，您需要将=替换为==或===。而prompt()只需要一个参数。

我试图找出如何让我的功能一个接一个地运行......但它不起作用

1 个答案: